Format your code properly with code tags and finish your for statements (3 parameters, not 2) and repost...
Then we have something readable to work with.
WaltP
Posting Sage w/ dash of thyme
10,492 posts since May 2006
Reputation Points: 3,348
Solved Threads: 943
If I understand right I needed to enclose my code in [] right?
No. You enclose the code in tags. You could possiblly use the PREVIEW button to see if your post looks right... ;)I re-wrote the for statements although I thought that it was okay to declare variables earlier in the program and just place a ";" in the place of the the variable declaration in the for statement? I was unable to get the k variable to compile without first declaring it.
Yes you should declare your variables earlier in the program. And yes you can just ";"if you know what you're doing. The first position is not a variable declaraction is a variable initialization, the first value the variable has thru the loop.
Also, formatting is of primary importance. Every time you use { indent 4 spaces. Just before you use every }, unindent.
Formatted properly, you code looks like:
#include <iostream>
#include <string>
using std::cin;
using std::string;
using std::cout;
using std::endl;
int main()
{
int i;
int j;
int k;
const char STAR ='*';
k=2; // What does this statement do for you?
// What's the value the second time thru the I loop?
for(i=0; i<7; i++)
{
for(j=0;j<k;j=j++)
{
cout << STAR;
}
{ // Why are you starting a new block?
for(k=0;k < 14; k= k+2)
cout << endl;
}
}
return 0;
} //end of main function
WaltP
Posting Sage w/ dash of thyme
10,492 posts since May 2006
Reputation Points: 3,348
Solved Threads: 943
I don't see the reason for the 3rd loop
for(int k = 0; k < 14; k += 2)
cout << endl;
You'll be outputting 7 newlines between rows of stars... is that what you meant to do?
Infarction
Posting Virtuoso
1,580 posts since May 2006
Reputation Points: 683
Solved Threads: 53
WaltP it never occured to me at the time to preview my post but your absolutely correct and thank you for the pointer on initialization of the variable.
Hmmmm.... no comment :) My thinking was that I since I needed to print six lines of star's that I would have the outer loop run six times, ...
Good thought.then I needed an inner loop to run six times but increment by 2 such that I would have another loop run 2 times, then 4, then 6, then 8, 10 and finally 12 times so that my cout <
You just complexed it out of reason.
Let's think about this... (yeah, I know that's what we're doing... ;))
You have one outer loop that goes from 0 to 6 for(i=0; i<7; i++)
That's 7 lines... What's wrong here? That you can fix easily.
Now you want 6 lines of 2, 4, 6, 8... *s. Your loop goes 0, 1, 2, 3...
Is there a correlation between what you want and your loop?
WaltP
Posting Sage w/ dash of thyme
10,492 posts since May 2006
Reputation Points: 3,348
Solved Threads: 943
Okay for your first question I should change the for statement to i<6
Yes now that you have pointed it out I see that there is a correlation between the two sets.
My outer loop is:
0, 1,2,3,4,5
the difference between that and what I need to print is
2,3,4,5,6,7
so the inner loop actually would appread to be the outer loop number +1 right?
so I could add 1 to i for the inner loop such as j=i+2; ?
Thank you
In both cases -- BINGO! Two loops is all you need. One outer for the lines, one inner for the *s based on teh line you're on...
WaltP
Posting Sage w/ dash of thyme
10,492 posts since May 2006
Reputation Points: 3,348
Solved Threads: 943