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C++ Discussion Thread
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Views: 1376

Feb 19th, 2007

can some one take a look at my program and help me

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Hey i need with this program it works, but i cant figure out how to make it not print out zeros when it is reversed. for example when the user types in 123000 it should print out 321. but my program prints out 000321 what can i do to make it print out 321.

C++ Syntax (Toggle Plain Text)
#include "stdafx.h"
#include <iostream>
#include <ctype.h>
#include <fstream>
#include <string>
using namespace std;
int reverseDigit, integer, reverse; 
 
int main()
{
 
 string integer;
 int cntr;
 cout <<"Please input an integer: ";
 cin >> integer;
 
 cntr = integer.size();
 cntr--;
  cout <<"reverse = "; 
 if (integer [0] == '-')
  {
   cout << "-";
  }
 while (cntr > -1)
  {    
   if (integer [cntr] == '-')
    cntr--;
   else 
    cout << (integer[cntr--]);
  }
 cout << endl;
 return 0;
 
}
#include "stdafx.h"
#include <iostream>
#include <ctype.h>
#include <fstream>
#include <string>
using namespace std;
int reverseDigit, integer, reverse; 

int main()
{

 string integer;
 int cntr;
 cout <<"Please input an integer: ";
 cin >> integer;

 cntr = integer.size();
 cntr--;
  cout <<"reverse = "; 
 if (integer [0] == '-')
  {
   cout << "-";
  }
 while (cntr > -1)
  {    
   if (integer [cntr] == '-')
    cntr--;
   else 
    cout << (integer[cntr--]);
  }
 cout << endl;
 return 0;

}

Last edited by ~s.o.s~; Feb 19th, 2007 at 1:04 pm. Reason: Added code tags, learn to use them.

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bigben09

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Feb 19th, 2007

Re: can some one take a look at my program and help me

Don't use global variables. Its a bad programming practice considering the job can be very well done using local ones.

As far as your method is considered its a bit unclean but still if you want to strip off the leading zeroes check one more condition which keeps skipping zero as long as it doesn't encounter a non zero valid digit.

Btw, I see no validation considering that the user is allowed to enter even alphabets and punctuations and get away with them...

~s.o.s~

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Failure as a human

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Feb 19th, 2007

Re: can some one take a look at my program and help me

how would i make it only eccept #'s and were would i put it in the program. also this is my first computer class so i am new to this so im not sure what u are talking about

bigben09

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Feb 19th, 2007

Re: can some one take a look at my program and help me

For right now don't worry about it. Verification of input will probably be later in the course.

WaltP

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Feb 19th, 2007

Re: can some one take a look at my program and help me

ok but does anyone know how i would make it not pass a zero if the first number is zero after it been reverset. for example 1230 shoul be printed out as 321 and not 0321.

bigben09

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Feb 21st, 2007

Re: can some one take a look at my program and help me

Click to Expand / Collapse Quote originally posted by bigben09 ...

ok but does anyone know how i would make it not pass a zero if the first number is zero after it been reverset. for example 1230 shoul be printed out as 321 and not 0321.

Sure. When you start outputting the values, check for a 0. If there is one, don't output it. Keep testing until you don't find a zero. Once you output that first non-zero, stop testing and just output to the end.

WaltP

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Feb 21st, 2007

Re: try this out

c Syntax (Toggle Plain Text)
#include "stdafx.h"
#include <iostream>
#include <ctype.h>
#include <fstream>
#include <string>
using namespace std;
int reverseDigit, integer, reverse; 
 
int main()
{
 
 string integer;
 int cntr,f=1;
 cout <<"Please input an integer: ";
 cin >> integer;
 
 cntr = integer.size();
 cntr--;
  cout <<"reverse = "; 
 if (integer [0] == '-')
  {
   cout << "-";
  }
 while (cntr > -1)
  {    
   if (integer [cntr] == '0'&&f=1)
    cntr--;
   else 
    {
       cout << (integer[cntr--]);
       f=0;
    }    
  }
 cout << endl;
 return 0;
 
}
#include "stdafx.h"
#include <iostream>
#include <ctype.h>
#include <fstream>
#include <string>
using namespace std;
int reverseDigit, integer, reverse; 
 
int main()
{
 
 string integer;
 int cntr,f=1;
 cout <<"Please input an integer: ";
 cin >> integer;
 
 cntr = integer.size();
 cntr--;
  cout <<"reverse = "; 
 if (integer [0] == '-')
  {
   cout << "-";
  }
 while (cntr > -1)
  {    
   if (integer [cntr] == '0'&&f=1)
    cntr--;
   else 
    {
       cout << (integer[cntr--]);
       f=0;
    }    
  }
 cout << endl;
 return 0;
 
}

Last edited by WaltP; Feb 21st, 2007 at 3:38 am. Reason: Added Code Tags -- please use them yourself. Instructions in the stickys.

goutham_see

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Feb 21st, 2007

Re: can some one take a look at my program and help me

Little typo I noticed in your code:

(Toggle Plain Text)

if (integer [cntr] == '0'&&f=1)

Last edited by John A; Feb 21st, 2007 at 8:19 pm.

John A

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