How do you code a series?

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I find a problem which says

An approximate value of pi can be calculated using the series given below:
Pi = 4 [ 1 – 1/3 + 1/5 – 1/7 + 1/9 … + ((-1)n)/(2n+1)]
Write a C++ program to calculate the approximate value of pi using this series. The program takes an input n that determines the number of terms in the approximation of the value of pi and outputs the approximation. Includes a loop that allows the user to repeat this calculation for new values n until the user says she or he wants to end the program.

As far as I know, the we can use the formula given in the problem, put it in the loop and using input from the user to determine when it should end. But I can't code it at all http://images.devshed.com/fds/smilies/mad.gif I mean... its like a series that keeps on going if not mistaken. How can I code this? Plus, it swtiches from + to - repeatedly. zz confused.

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ice_tea_lemon

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Mar 16th, 2007

Re: How do you code a series?

C version: returns pi/4

C++ Syntax (Toggle Plain Text)
#include <stdlib.h>
 
double pi_over_4(int n)
{
	double iter=3;
	int eveodd=1;
	double pi=0.;
 
    for(pi=1.; n>0; n--, iter+=2., eveodd=!eveodd)	
	{		
		if(eveodd)
		    pi-=1./iter;
		else				
	                    pi+=1./iter;
	}	
	return pi;
}
#include <stdlib.h>

double pi_over_4(int n)
{
	double iter=3;
	int eveodd=1;
	double pi=0.;

    for(pi=1.; n>0; n--, iter+=2., eveodd=!eveodd)	
	{		
		if(eveodd)
		    pi-=1./iter;
		else				
	                    pi+=1./iter;
	}	
	return pi;
}

Last edited by jim mcnamara; Mar 16th, 2007 at 3:37 pm.

jim mcnamara

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