date difference in c++

[animesh]

how to subtract two dates to find no of days .

[meabed]

i think that you can use

enum

it is as

structure

but enum list the elements by index as array .. for example[code]
enum days_of_the_week ={sat,sun,mon,tue,wed,thu,fri };
there for .. sat has the value 0 and sun = 1 and mon = 2 and so on ..
so if u say mon - sat
the compiler wil supstract the values only ... ther for u will get 2 .

[Dave Sinkula]

This is one way.

<strong>#include</strong> <iostream>
<strong>#include</strong> <ctime> 
 
<strong>int</strong> <strong>main</strong>() 
{
<strong>   struct</strong> std::tm a = {0,0,0,24,5,104}; /* June 24, 2004 */
<strong>   struct</strong> std::tm b = {0,0,0,5,6,104}; /* July 5, 2004 */
   std::time_t x = std::<strong>mktime</strong>(&a);
   std::time_t y = std::<strong>mktime</strong>(&b);
<strong>   if </strong>( x != (std::time_t)(-1) && y != (std::time_t)(-1) )
   {
	 <strong>double</strong> difference = std::<strong>difftime</strong>(y, x) / (60 * 60 * 24);
	 std::<strong>cout</strong> << std::ctime(&x);
	 std::<strong>cout</strong> << std::ctime(&y);
	 std::<strong>cout</strong> << "difference = " << difference << " days" << std::<strong>endl</strong>;
   }
<strong>   return</strong> 0; 
}
 
/* my output
Thu Jun 24 01:00:00 2004
Mon Jul 05 01:00:00 2004
difference = 11 days
*/