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C++ Discussion Thread
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Aug 20th, 2007

confirmation of LOOP

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hey guyz!!! i'm just trying to check my code u all if it's correct. thankz!

the problem is " ask a number (N). calculate and display the value of x, where x = (1*N)+(2*N)+(3*N)...(N*N);
ex. if i input a number 5 the formula of x where: x = (1*N)+(2*N)+(3*N)+(4*N)+(5*N);

this is my code:

C++ Syntax (Toggle Plain Text)
#include <iostream>
int main ()
{
int n,x,y;
	y=0;
	    cout<<"\nEnter number: ";
	      cin>>n;
 
	while (y<=n)
	    {
 
	    cout<<"\n"<<y;
	    y++;
	    x += (y*n);
 
	    }
		   cout<<"\n\nx = "<<x;
 
               return 0;
}
#include <iostream>
int main ()
{
int n,x,y;
	y=0;
	    cout<<"\nEnter number: ";
	      cin>>n;

	while (y<=n)
	    {

	    cout<<"\n"<<y;
	    y++;
	    x += (y*n);

	    }
		   cout<<"\n\nx = "<<x;

               return 0;
}

Last edited by Ancient Dragon; Aug 20th, 2007 at 10:12 pm. Reason: add code tags

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Aug 20th, 2007

Re: confirmation of LOOP

>>i'm just trying to check my code u all if it's correct
does it do what its supposed to do ? If yes, then its ok. If not then you need to fix it. One problem though is that your program will produce data overflow errors if the value of n is too large.

Last edited by Ancient Dragon; Aug 20th, 2007 at 10:15 pm.

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Aug 20th, 2007

Re: confirmation of LOOP

not! the display is different with my calculation on my own..
x += (y*n); << i'm not sure with this formula...
can you help me with this?

hoceandress

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Re: confirmation of LOOP

The value of x is uninitialized, and the value of y should start at 1 not 0. It might be better to use a for loop instead of a while loop.

Last edited by Ancient Dragon; Aug 20th, 2007 at 10:31 pm.

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Re: confirmation of LOOP

NICE ONE MAN!! I GOT IT!! THANKS, MORE POWER TO YOU...

i'm using the "for loop" its results, like my calculation...huh!

hoceandress

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Re: confirmation of LOOP

(1*n)+(2*n)+(3*n)...(n*n) == (1+2+3+..+n)*n == (n+1)/2*n*n

Last edited by vijayan121; Aug 20th, 2007 at 10:57 pm.

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