Hello, i am trying to count from 0 - 7 and storing the values in an array.
I have been trying to do this solidly for 2 weeks
my attempt:
**************************************
int a[20];
int x;
for ( x=0 ; x<=7 ; x++ ) {
a[1] = x;
cout << x << endl; }
***************************************
I know that the output from this program is correct, i.e. it displays:
0
1
2
.
.
7
my problem is a[1] will only display the value inside the for loop's {}. I want to use an array element, a[1] outside of the for { } with those values stored in there. Please help!
Thanks,
John
Last edited by johnnyjohn20; Nov 22nd, 2007 at 3:59 pm. Reason: inserted wrong code
As salem told you, exchanging a[1] whit 'a[x]' should solve your problems.
In your code you constantly over-wrights position 1 in the array, and leaving all the others untouched. If you try to display a[1] after the loop have finished, it will display '7'.
Thank you for your help, so far i have adjusted the code and can now display the values outside of the { }, using
cout << a[1] << endl;
cout << a[2] << endl; ...etc etc. Is there a way i can display all of the values in the array using one simple command?.
Thanks for your time reading my posts!
Last edited by johnnyjohn20; Nov 22nd, 2007 at 4:47 pm.
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