counting a few numbers and storing the values

[johnnyjohn20]

Hello, i am trying to count from 0 - 7 and storing the values in an array.

I have been trying to do this solidly for 2 weeks :'(

my attempt:

**************************************
int a[20];
int x;

for ( x=0 ; x<=7 ; x++ ) {

a[1] = x;
cout << x << endl; }

***************************************

I know that the output from this program is correct, i.e. it displays:
0
1
2
.
.
7

my problem is a[1] will only display the value inside the for loop's {}. I want to use an array element, a[1] outside of the for { } with those values stored in there. Please help!

Thanks,

John

[Salem]

> a[1] = x;
Perhaps
a[x] = x;

[jansson]

Hello johnnyjohn20.

As salem told you, exchanging a[1] whit 'a[x]' should solve your problems.
In your code you constantly over-wrights position 1 in the array, and leaving all the others untouched. If you try to display a[1] after the loop have finished, it will display '7'.

[johnnyjohn20]

Thank you for your help, so far i have adjusted the code and can now display the values outside of the { }, using
cout << a[1] << endl;
cout << a[2] << endl; ...etc etc. Is there a way i can display all of the values in the array using one simple command?.

Thanks for your time reading my posts!

[Salem]

Use the same kind of for loop you used to fill the array perhaps?