Member Avatar for castajiz_2

I would like to know if there is a class wich generates RANDOM words which have sense(are in use in the daily language in englis). I am making a project where uppon a given random generated word i would like to collect letters for that given word so once i collect the letters it should match the generated word. Or if there isn t please give me a suggestion how to do this.

  • 3 Contributors
  • 3 Replies
  • 296 Views
  • 1 Day Discussion Span
  • Latest Post Latest Post by castajiz_2

Dani AI

Generated

Building on and — and since already pulled a raw word list from the web — here is a practical, Python-first way to turn that file into reliably playable, “real” English words and a couple of tips to make the generator behave the way you want.

A minimal, working approach: normalize and filter the list, then pick from a length-limited pool. If you want everyday vocabulary, prefer sampling from a frequency-ranked list (top N words) or use weights rather than uniform choice.

import random, re

def load_wordlist(path):
    with open(path, 'r', encoding='utf-8') as f:
        words = [w.strip().lower() for w in f]
    # keep only simple alphabetic words
    return sorted(set(w for w in words if re.fullmatch(r'[a-z]+', w)))

words = load_wordlist('words.txt')

def random_word(min_len=3, max_len=8):
    pool = [w for w in words if min_len <= len(w) <= max_len]
    return random.choice(pool)

def weighted_random_word(freq_pairs, min_len=3, max_len=8):
    pool = [(w,c) for w,c in freq_pairs if min_len <= len(w) <= max_len]
    candidates, weights = zip(*pool)
    return random.choices(candidates, weights=weights, k=1)[0]  # Python 3.6+

For more natural-sounding generation (expanding on ): build a prefix tree where each node stores how many words continue through it and how many end there. Then choose the next letter by sampling children weighted by their subtree counts; allow termination with probability proportional to the node’s end count. That produces only real words (if built from a real list) and naturally biases toward common continuations.

Quick troubleshooting and game tips: filter out one-letter and extremely long words, ensure selected words contain vowels for playability, and trim the list to the top N most frequent words if players should see familiar vocabulary. Watch file encoding and licensing of any wordlist you use.

Recommended Answers

All 3 Replies

Member Avatar for ddanbe

The only thing I can come up with is that you have an English dictionary in a database and you pick random words out of it.
A real random word generator should at least take account of the fact that there are few words that don't contain vowels.

Member Avatar for Momerath

Take a list of words and build a Trie from them, make random choice at each branch for which letter comes next.

You'll need to learn what a Trie is, and how to use it :)

Member Avatar for castajiz_2

i found a website where there are plenty of words and i downloaded them to my project using the WebClient class and the DownloadString method inside that class.

Be a part of the DaniWeb community

We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.