decimal to hexadecimal

0

By dhiyauddin on Sep 28th, 2009 11:40 am

/**
* @(#)dayau_0.java
*
* dayau_0 application
*
* @author
* @version 1.00 2009/9/28
*/

public class dayau_0 {

public static void main(String[] args) {

int num = 30;
String AnsHex = "";
AnsHex = DectoHexDec(num);
System.out.println(AnsHex);
}

public static int DectoHexDec(int x) {

String result = "";
int remainder = 0;
while (x>0){
remainder = x%16;
switch(remainder){
case 1 : result = Integer.toString(remainder)+result;
break;
case 2 : result = Integer.toString(remainder)+result;
break;
case 3 : result = Integer.toString(remainder)+result;
break;
case 4 : result = Integer.toString(remainder)+result;
break;
case 5 : result = Integer.toString(remainder)+result;
break;
case 6 : result = Integer.toString(remainder)+result;
break;
case 7 : result = Integer.toString(remainder)+result;
break;
case 8 : result = Integer.toString(remainder)+result;
break;
case 9 : result = Integer.toString(remainder)+result;
break;
case 10 : result = "A"+result;
break;
case 11 : result = "B"+result;
break;
case 12 : result = "C"+result;
break;
case 13 : result = "D"+result;
break;
case 14 : result = "E"+result;
break;
case 15 : result = "F"+result;
break;
}
x = x/16;
}
return result;
}
}

/**
 * @(#)dayau_0.java
 *
 * dayau_0 application
 *
 * @author 
 * @version 1.00 2009/9/28
 */
 
public class dayau_0 {
    
    public static void main(String[] args) {
    	
    int num = 30;
    String AnsHex = "";
    AnsHex = DectoHexDec(num);
    System.out.println(AnsHex);
    }
    
    public static int DectoHexDec(int x) {
    
    String result = "";
    int remainder = 0;
    while (x>0){
    	remainder = x%16;
    	switch(remainder){
    		case 1 : result = Integer.toString(remainder)+result;
 			break;   
    		case 2 : result = Integer.toString(remainder)+result;
 			break;
    		case 3 : result = Integer.toString(remainder)+result;
 			break; 			
    		case 4 : result = Integer.toString(remainder)+result;
 			break;
    		case 5 : result = Integer.toString(remainder)+result;
 			break; 			
 			case 6 : result = Integer.toString(remainder)+result;
 			break;	
    		case 7 : result = Integer.toString(remainder)+result;
 			break; 				
    		case 8 : result = Integer.toString(remainder)+result;
 			break; 				
    		case 9 : result = Integer.toString(remainder)+result;
 			break;
    		case 10 : result = "A"+result;
 			break;
    		case 11 : result = "B"+result;
 			break;
    		case 12 : result = "C"+result;
 			break; 			
    		case 13 : result = "D"+result;
 			break; 			 			 			 				
    		case 14 : result = "E"+result;
 			break; 			
    		case 15 : result = "F"+result;
 			break; 			
 				}
 		x = x/16;
 		}
 	return result;
    }
}

2 Years Ago

0

Do you have a question?

masijade

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2 Years Ago

Show Comments

1

Why the lengthy switch rather than something like

result = "023456789ABCDEF".charAt(remainder) + result;

JamesCherrill

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2 Years Ago

0

won't work for number with remainder zero...so insert case 0....

daredevilnitte

Newbie Poster

1 post since Oct 2009

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2 Years Ago

0

If you rplace the ludicrous switch with the single line
result = "023456789ABCDEF".charAt(remainder) + result;
then you won't have that problem anyway.

JamesCherrill

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6,373 posts since Apr 2008

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8 Months Ago

0

Theres one problem with this program, the DectoHexDec method header is "public static int DectoHexDec(int x)", but then proceeds to return a string, so that needs to be fixed.

doomsday1216

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7 posts since Sep 2011

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8 Months Ago

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@doomsday1216 and what would be suitable fix according to you? I'm interested to hear about it.

peter_budo

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6 Months Ago

0

@doomsday1216 and what would be suitable fix according to you? I'm interested to hear about it.

just change int to String (e.g. instead of public static int DectoHexDec(int x), just make it public static String DecToHexDec(int x) )

doomsday1216

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6 Months Ago

0

Why the lengthy switch rather than something like

result = "023456789ABCDEF".charAt(remainder) + result;

In theory, .charAt returns a char, and result is a string. this can be fixed by changing result to an array of chars, and then put a small for loop to put each character into a string. This may seem convoluted, but it's still faster than the massive case/switch block. The for loop would look something like this.

String done="";
		for(int j=0;j<result.length;j++)
		{
			done=result[j]+done;
		}

doomsday1216

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7 posts since Sep 2011

Reputation Points: 10

Solved Threads: 0

decimal to hexadecimal

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