Hi .Facing problem while displaying LinkedList (API) element using Iterator

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Hi

I have a LinkedList of class called Room. Now i want display elements that i stored in that class . i also implemented toString() in my Room class which returns string.

The code i tried is below but its not working . i dont know the reason . can anyone help me .

Java Syntax (Toggle Plain Text)
private static void callDisplay(LinkedList<Room> roomlist) {
		// TODO Auto-generated method stub
		ListIterator<Room> iter = roomlist.listIterator();	
		while (  iter.hasNext() )
		{  
			System.out.println("Came in");
			Room r = iter.next();
			r.toString();
 
		}
 
	}
private static void callDisplay(LinkedList<Room> roomlist) {
		// TODO Auto-generated method stub
		ListIterator<Room> iter = roomlist.listIterator();	
		while (  iter.hasNext() )
		{  
			System.out.println("Came in");
			Room r = iter.next();
			r.toString();
			
		}
		
	}

Aashath

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Oct 22nd, 2008

Re: Hi .Facing problem while displaying LinkedList (API) element using Iterator

The r.toString() returns a String, it does not print. You need to call System.out.println() with argument r or r.toString()

javaAddict

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Oct 22nd, 2008

Re: Hi .Facing problem while displaying LinkedList (API) element using Iterator

When you say it's not working, are you getting an error message? Does the string "Came in" print? If the answer is no to both questions then there are no Room objects in your LinkedList. Try a call to roomList.size() to see how many are Room objects exist in your list.

If you are getting the string "Came in" printed, then the problem is that you are just writing r.toString() - you don't actually do anything with that call like print it. Try

java Syntax (Toggle Plain Text)
System.out.println( r.toString() );
System.out.println( r.toString() );

instead.

darkagn

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