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Dec 5th, 2008

help with watch program

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Please help me with a simple watch program.
In the program,I have to display on the same line.
i have written the following code which is not working.
pls look into it

(Toggle Plain Text)

class watch
{
	private int h,m,s,a=0,b=0;

	public void calc()
	{
		
		for(;a==b;s++)
		{
			if(s%60==1)
			{
				m++;
			}

			if(m%60==1)
			{
				h++;
			}

			System.out.println(h+" : "+m+" : "+s);

			Thread.getThread().sleep(1000);
		}

	}
	public static void main(String args[])
	{
		watch w1=new watch();
		w1.calc();
	}

}

The highlighted statement gives an error.
pls help me with the logic of displaying it on the same line.
thanks

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shubhang

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Dec 5th, 2008

Re: help with watch program

Let me guess "un-catch exception". Put that section in try/catch exception and catch InterruptedException (API)

Last edited by peter_budo; Dec 5th, 2008 at 2:08 pm. Reason: add link

peter_budo

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Dec 5th, 2008

Re: help with watch program

Rather I would say the error is from calling methods that do not exist on the Thread class.

Ezzaral

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Dec 6th, 2008

Re: help with watch program

first of all, what is the value of variable (s) here in the program, it is assumed here as it is zero , is it the value that you want it or not

secondly the looping will be infinite because value of variable (a) and value of variable (b) is always same , therefore check it again to make the loop finite

hope it helps
thanks

alsoumhi

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Dec 6th, 2008

Re: help with watch program

Hello, shubhang.
You've asked:

Quote ...

pls help me with the logic of displaying it on the same line.

Here is a few articles about positioning cursor in console application:
http://mindprod.com/jgloss/console.html
http://en.allexperts.com/q/Java-1046...or-console.htm
http://www.rgagnon.com/javadetails/java-0469.html
Hope it can help

Last edited by Antenka; Dec 6th, 2008 at 3:26 pm.

Antenka

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