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Single Linked Circular Link List

Does anyone know how to fully set up a circular linked list, and its methods, remove, insert, and find?

Here is what i have so far but i have no idea if its proper

public class CLL
{
public class Node
{
int item;
Node next;

public Node()
{
this.item = 0;
this.next = null;
}
public Node(int e, Node n)
{
item = e;
next = n;
}
}
Node head;

public void insert(int item)
{
if(head == null)
{
head = new Node(item,null);
head.next = head;
}
else
{
head.next = new Node(item,head.next);
}
}
public void remove(int item)
{

}
public int find(int item)
{

}
}

First is my insert right? I think it is, but I keep feeling I may have missed something, and secondly, I have no idea how to do the remove function, or the find function If someone has code to help me it would be very awesome

kharri5
Junior Poster in Training
56 posts since Jan 2005
Reputation Points: 13
Solved Threads: 0
 

You insert looks right.
For remove you should really make a small drawing on paper on what you need to do.
Find the record to remove, and set the next of the record before it to the record next of the record you want to remove is pointing to.
That's all.
And oh, do remember to pass back a reference to an item still in the list from the remove function. Else the program using the list might loose the list if you remove the point where the program hooks into the list, which would have you effectively delete the entire list except the item you want to remove from it.

In a circular linked list it's impossible to find items based on an index. After all, there is no starting point!
You could give each item an index number and loop through the list from some point (you need to keep a reference to something in the list after all somewhere or the whole thing gets impossible to reach).

jwenting
duckman
Team Colleague
8,392 posts since Nov 2004
Reputation Points: 1,662
Solved Threads: 337
 

Well here is my remove and find functions. Are these correct? I didn't know what you meant by this part:

you wrote:==================================================
And oh, do remember to pass back a reference to an item still in the list from the remove function. Else the program using the list might loose the list if you remove the point where the program hooks into the list, which would have you effectively delete the entire list except the item you want to remove from it.
==========================================================

public void remove(int key)
{
Node current = head;
do
{
if(current.next.item == key )
{
Node temp = current.next;
current = temp.next;
if(temp == head)
{
head = head.next;
}
temp = null;
break;
}
current = current.next;
} while(current != head);
}
public int find(int key)
{
Node p = head;
while(p!=null && !(p.item == key))
{
p = p.next;
if(p!= null)
{
return p.item;
}
}
return 0;
}

I can't tell if the logic on those are both correct or not, because when using it, it turned up values, that I don't think were correct. Hope you can help, me cause its breakin ma balls

kharri5
Junior Poster in Training
56 posts since Jan 2005
Reputation Points: 13
Solved Threads: 0
 
In a circular linked list it's impossible to find items based on an index. After all, there is no starting point!

depends on how you code it! If you have a starting head node you can index from there

1o0oBhP
Posting Pro in Training
445 posts since Dec 2004
Reputation Points: 16
Solved Threads: 6
 

http://www.dreamincode.net/forums/showtopic50999.htm

The question is write a java program which maintains the data inside single linked list.The program needs to insert,delete and search and print the data using the main menu,The data should contain information about the newborn baby.

so is it right atleast partially:D

class Baby{

private string lastName;
private string firstName;
private int age;
public baby( stringlast,string first,inta)

{
lastName = last;
firstName = first;
age = a;
}

}

public void display()

{
System.out.print("Lastname:"+ lastName);
System.out.print("Firstname:"+ firstName);
System.out.print("age:"+ age);

}

public find(String searchName)
{
int i;

for (i = 0; i< nElems;j++)
if( a[i].getLast().equals(SearchName))
break;
if(j == nElems)

return null;
else
return a[i];
}


public insert( String last,String first,int a)

{
a [nElems] = new Baby(last,first,age)
nElems ++;

}

public boolean delete (String searchName)

{
int i ;
for ( i = 0;i < nElems;i++)

if( a[i].getLast().equals(SearchName))
break;
if(j == nElems)
return false;


else
{

for (int j = i;j

aylin
Newbie Poster
1 post since Nov 2009
Reputation Points: 10
Solved Threads: 0
 

i need a program on circular single linked list

roopa09
Newbie Poster
1 post since Dec 2009
Reputation Points: 10
Solved Threads: 0
 

This article has been dead for over three months

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