i want to find the second smallest number ib array but it is displaying second highest number
int max=0,second=0;
if(a[0]>a[1])
{
max=a[0];
second=a[1];
}
else
{
max=a[1];
second=a[0];
}
for( i=2;i<n;i++)
{
if(a[i]>=max)
{
second=max;
max=a[i];
}
else

if(a[i]>second)
second=a[i];

}
System.out.println("the second smallest nubmer is"+second);

Already I can see problem here, in both cases if/else statement will be useless if first two numbers will be some of largest. You are expecting smallest number to be on one of first two positions in array.
Consider following array and think about it again
arr = {4, 5, 1, 3, 2}