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Sep 6th, 2007

Else If statement

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Hello everyone, I just need help on this code. I can't debug it, I'm just new in Java and this is just my fifth assignment so I'm really having a hard time.

Here's my code:

Java Syntax (Toggle Plain Text)
import java.io.*;
public class input
{
    public static InputStreamReader Reader=new
    InputStreamReader (System.in);
    public static BufferedReader input=new 
    BufferedReader(Reader);
    public static void main(String args[]);
    String name;
    int age;
    double salary;
    {
    System.out.println("Enter name:");
    name=input.readline();
    System.out.println("Enter age:");
    age=Integer.parseInt(input.readLine());
    if(age<=18)
    System.out.println("Too young!");
    }
    else if (age>=18);
    {
    System.out.println("You're ready to vote!");
    }
    }
import java.io.*;
public class input
{
    public static InputStreamReader Reader=new
    InputStreamReader (System.in);
    public static BufferedReader input=new 
    BufferedReader(Reader);
    public static void main(String args[]);
    String name;
    int age;
    double salary;
    {
    System.out.println("Enter name:");
    name=input.readline();
    System.out.println("Enter age:");
    age=Integer.parseInt(input.readLine());
    if(age<=18)
    System.out.println("Too young!");
    }
    else if (age>=18);
    {
    System.out.println("You're ready to vote!");
    }
    }

the Error says that:
illegal start of type line 20
<identifier> expected line 20

Java Syntax (Toggle Plain Text)
else if (age>=18);
else if (age>=18);

Can anyone please tell me how to debug it? =/

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rapperhuj

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Sep 6th, 2007

Re: Else If statement

Your braces and semicolons are out of place. Look through your if () else if () block and check them.

Ezzaral

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Sep 6th, 2007

Re: Else If statement

uhmmm.. I'm sorry, but I already tried to move the braces at the "else if" line. Still I can't let it run. =(

rapperhuj

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Sep 6th, 2007

Re: Else If statement

Look at the structure of your class and main() method and compare that with your other assignments which do run. Also, look at the brace structure of any if-else block. The problems should be reasily apparent to you.

This is about as basic as debugging can get and you need to spot the problems on your own to learn. I've already told you what the nature of the problem is, so all you have to do is look at those blocks.

Ezzaral

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Sep 6th, 2007

Re: Else If statement

ok.. thx.. I'll check them.. =)

rapperhuj

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Sep 6th, 2007

Re: Else If statement

arg.. a new error occured. >.< this is my only notes/guide for the if else statement. =(

Java Syntax (Toggle Plain Text)
import java.io.*;
public class input{
    public static InputStreamReader Reader=new 
    InputStreamReader(System.in);
    public static BufferedReader input=new 
    BufferedReader(Reader);
    public static void main(String args[]){
    String name;
    int age;
    {
    System.out.println("Enter name:");
    name=input.readLine();
    System.out.println("Enter age:");
    age=Integer.parseInt(input.readLine());
    if (age<=17){
    System.out.println("Too young!");
    } else if(age>=18){
    System.out.println("You're ready to vote!");
    }
    }
    }
}
import java.io.*;
public class input{
    public static InputStreamReader Reader=new 
    InputStreamReader(System.in);
    public static BufferedReader input=new 
    BufferedReader(Reader);
    public static void main(String args[]){
    String name;
    int age;
    {
    System.out.println("Enter name:");
    name=input.readLine();
    System.out.println("Enter age:");
    age=Integer.parseInt(input.readLine());
    if (age<=17){
    System.out.println("Too young!");
    } else if(age>=18){
    System.out.println("You're ready to vote!");
    }
    }
    }
}

The error says:
- unreported exception java.io.IOException; must be caught or
declared to be thrown line 12

Java Syntax (Toggle Plain Text)
name=input.readLine();
name=input.readLine();

- unreported exception java.io.IOException; must be caught or
declared to be thrown line 14

Java Syntax (Toggle Plain Text)
age=Integer.parseInt(input.readLine());
age=Integer.parseInt(input.readLine());

It seems like my teacher forgot something or I copied the code wrong. =(

Last edited by rapperhuj; Sep 6th, 2007 at 10:48 pm.

rapperhuj

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Sep 7th, 2007

Re: Else If statement

I do not know what your teacher gave it to you and if you already covered Exceptions, but that what you get when you use BufferedReader getLine().
Check this tutorial and you should be able to figure it out what to do with it. Main difference between yours code and code in the tutorials is that you read from command line and tutorial do it from a file

peter_budo

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Sep 7th, 2007

Re: Else If statement

Using Scanner to read the input would be easier and you wouldn't have to mess with the ioexception.
http://java.sun.com/javase/6/docs/ap...l/Scanner.html

Ezzaral

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Sep 7th, 2007

Re: Else If statement

or just add

throws IOException

underneath your main method declaration.

...
public static void main(String args[])
throws IOException {
String name;
...

that should work.

thenava

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Sep 7th, 2007

Re: Else If statement

Click to Expand / Collapse Quote originally posted by thenava ...

or just add

throws IOException

underneath your main method declaration.

...
public static void main(String args[])
throws IOException {
String name;
...

that should work.

No, main really should not throw exceptions. How do you intend to handle an exception that is thrown beyond the scope of your execution?

The catch block should be placed within main() and handle the exception gracefully.

Ezzaral

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