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Sep 9th, 2007

I can't display the right output (else if statement)

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Hi everyone, I hope you guys can help me.

Output

Enter your department number:
You belong to:

1-3 = Mr.X
4-7 = Mr.Y
8-9 = Mr.Z

------
Error:
When I input numbers from 1-9, the output that is displayed is always "You belong to: Mr. Z"

Here's my code:

Java Syntax (Toggle Plain Text)
import java.io.*;
public class Test5
{
	public static BufferedReader input=new BufferedReader (new InputStreamReader(System.in));
	public static void main(String args[])
	{
		String Department;
		int dept=0;
		try{
		System.out.println("Enter Department:");
		Department=input.readLine();
		}
		catch(IOException ioe) {}
 
		if (dept<=9){
		System.out.println("You belong to: Mr.Z");
		}else if (dept<=7){
		System.out.println("You belong to: Mr.Y");
		}else if (dept<=3){
		System.out.println("You belong to: Mr.X");
		}
	}
}
import java.io.*;
public class Test5
{
	public static BufferedReader input=new BufferedReader (new InputStreamReader(System.in));
	public static void main(String args[])
	{
		String Department;
		int dept=0;
		try{
		System.out.println("Enter Department:");
		Department=input.readLine();
		}
		catch(IOException ioe) {}
		
		if (dept<=9){
		System.out.println("You belong to: Mr.Z");
		}else if (dept<=7){
		System.out.println("You belong to: Mr.Y");
		}else if (dept<=3){
		System.out.println("You belong to: Mr.X");
		}
	}
}

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iCez

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since Sep 2007

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Sep 9th, 2007

Re: I can't display the right output (else if statement)

numbers between 1-9 always are <=9. so you must specify an interval inside if-if else clause
like :
if(dept>7 && dept<=9)
System.out.println("You belong to: Mr.Z");
}else if (dept>3 && dept<=7){
System.out.println("You belong to: Mr.Y");
}else if (dept<=3){
System.out.println("You belong to: Mr.X");
}

ede

Reputation Points: 10

Solved Threads: 2

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since Aug 2006

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Sep 9th, 2007

Re: I can't display the right output (else if statement)

@ede
I tried your suggestion, but the output always display "you belong to Mr.X" =(

Java Syntax (Toggle Plain Text)
import java.io.*;
public class Test5
{
	public static BufferedReader input=new BufferedReader (new InputStreamReader(System.in));
	public static void main(String args[])
	{
		String Department;
		int dept=0;
		try{
		System.out.println("Enter Department:");
		Department=input.readLine();
		}
		catch(IOException ioe) {}
 
		if (dept>7&&dept<=9){
		System.out.println("You belong to: Mr.Z");
		}else if (dept>3&&dept<=7){
		System.out.println("You belong to: Mr.Y");
		}else if (dept<=3){
		System.out.println("You belong to: Mr.X");
		}
	}
}
import java.io.*;
public class Test5
{
	public static BufferedReader input=new BufferedReader (new InputStreamReader(System.in));
	public static void main(String args[])
	{
		String Department;
		int dept=0;
		try{
		System.out.println("Enter Department:");
		Department=input.readLine();
		}
		catch(IOException ioe) {}
		
		if (dept>7&&dept<=9){
		System.out.println("You belong to: Mr.Z");
		}else if (dept>3&&dept<=7){
		System.out.println("You belong to: Mr.Y");
		}else if (dept<=3){
		System.out.println("You belong to: Mr.X");
		}
	}
}

I also tried, but the error is still the same. >.<

Java Syntax (Toggle Plain Text)
if (dept<=3){
   System.out.println("You belong to: Mr.X");
   }else if (dept>=4&&dept<=7){
   System.out.println("You belong to: Mr.Y");
   }else if (dept>=8&&dept<=9){
   System.out.println("You belong to: Mr.Z");
   }
if (dept<=3){
   System.out.println("You belong to: Mr.X");
   }else if (dept>=4&&dept<=7){
   System.out.println("You belong to: Mr.Y");
   }else if (dept>=8&&dept<=9){
   System.out.println("You belong to: Mr.Z");
   }

Last edited by iCez; Sep 9th, 2007 at 4:43 am.

iCez

Reputation Points: 10

Solved Threads: 0

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since Sep 2007

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Sep 9th, 2007

Re: I can't display the right output (else if statement)

Same mistake in both cases

you store user input into Department but compared variable is dept, I think you forgot to parse String Department to integer dept so whole time you run check on null value of dept int dept=0;
your last attempt iCez actually work once parse implemented
Java Syntax (Toggle Plain Text)
```
if (dept<=3){
   System.out.println("You belong to: Mr.X");
   }else if (dept>=4&&dept<=7){
   System.out.println("You belong to: Mr.Y");
   }else if (dept>=8&&dept<=9){
   System.out.println("You belong to: Mr.Z");
   }
```
if (dept<=3){ System.out.println("You belong to: Mr.X"); }else if (dept>=4&&dept<=7){ System.out.println("You belong to: Mr.Y"); }else if (dept>=8&&dept<=9){ System.out.println("You belong to: Mr.Z"); }
Another option is code bellow which also deal with number out of boundaries 1 - 9

Java Syntax (Toggle Plain Text)
import java.io.*;
public class Test5
{
	public static BufferedReader input=new BufferedReader (new InputStreamReader(System.in));
	public static void main(String args[])
	{
		String Department;
		int dept=0;
		try{
		System.out.println("Enter Department:");
		Department=input.readLine();
		dept = (int) Integer.parseInt(Department);
		}
		catch(IOException ioe) {}
 
		if(dept>7 && dept<10){
		System.out.println("You belong to: Mr.Z");
		}else if (dept>3 && dept<8){
		System.out.println("You belong to: Mr.Y");
		}else if (dept>0 && dept<4){
		System.out.println("You belong to: Mr.X");
		}
		else{
		System.out.println("Department not recognice");
		}
	}
}
import java.io.*;
public class Test5
{
	public static BufferedReader input=new BufferedReader (new InputStreamReader(System.in));
	public static void main(String args[])
	{
		String Department;
		int dept=0;
		try{
		System.out.println("Enter Department:");
		Department=input.readLine();
		dept = (int) Integer.parseInt(Department);
		}
		catch(IOException ioe) {}
		
		if(dept>7 && dept<10){
		System.out.println("You belong to: Mr.Z");
		}else if (dept>3 && dept<8){
		System.out.println("You belong to: Mr.Y");
		}else if (dept>0 && dept<4){
		System.out.println("You belong to: Mr.X");
		}
		else{
		System.out.println("Department not recognice");
		}
	}
}

peter_budo

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Sep 9th, 2007

Re: I can't display the right output (else if statement)

@peter_budo
thx for the help! Actually I didn't forgot the parse thing, I just don't know how it works. >.< We we're not yet taught about that. ~.~

Thx anyway, it was a big help. ^^

Last edited by iCez; Sep 9th, 2007 at 5:58 am.

iCez

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