convert delphi to vb 6.0

[poilkjmnb]

Hello Friends,

Any body help me to convert the code from Delphi to vb 6.0

const
C1 = 43941;
C2 = 16302;

function BorlandEncrypt(const S: String; Key: Word): String;
var
I: byte;
begin
SetLength(Result,Length(S));
for I := 1 to Length(S) do begin
Result[I] := char(byte(S[I]) xor (Key shr 8));
Key := (byte(Result[I]) + Key) * C1 + C2;
end;
end;

function Encrypt(password : string) : string;
begin
{ ----old encrypt ----
result := '';
for i := 1 to length(password) do
result := result + char( (ord(password[i]) xor 43) + 11 ); }

// new encrypt
password := BorlandEncrypt(password,17732);
Result := '<' + Encode64(password) + '>';
//Result := '<' + Encode64(password) + '>';
end;

function Encode64(st : string) : string;
////////////////////////////////////////////////////////////////////////////////
// Base64 Encode a string (RFC 1521)
// Copyright © 2001 - Renier Crause
var
i,idx : integer;
begin
Result := '';
i := 1;
while i <= length(st) do
begin
// 1st char
idx := ord(st[i]) and $FC shr 2;
Result := Result + Alphabet[idx+1];
// 2nd char
idx := (ord(st[i]) and $3 shl 4);
if i+1 <= length(st) then idx := idx + (ord(st[i+1]) and $F0 shr 4);
Result := Result + Alphabet[idx+1];
// 3rd char
if i+1 <= length(st) then
begin
idx := (ord(st[i+1]) and $F shl 2);
if i+2 <= length(st) then idx := idx + (ord(st[i+2]) and $C0 shr 6);
Result := Result + Alphabet[idx+1];
end
else
Result := Result + '=';
// 4th char
if i+2 <= length(st) then
begin
idx := (ord(st[i+2]) and $3F);
Result := Result + Alphabet[idx+1];
end
else
Result := Result + '=';
// next source char
Inc(i,3);
end;
end;

Thanks,

[LizR]

What have you got so far? We dont tend to do your work for you!

[poilkjmnb]

What have you got so far? We dont tend to do your work for you!

Hello Lizr,

i m not work in delphi but i need to convert it to vb 6.0 for my application. can u help me to convert this code

function Encode64(st : string) : string;
////////////////////////////////////////////////////////////////////////////////
// Base64 Encode a string (RFC 1521)
// Copyright © 2001 - Renier Crause
var
i,idx : integer;
begin
Result := '';
i := 1;
while i <= length(st) do
begin
// 1st char
idx := ord(st[i]) and $FC shr 2;
Result := Result + Alphabet[idx+1];
// 2nd char
idx := (ord(st[i]) and $3 shl 4);
if i+1 <= length(st) then idx := idx + (ord(st[i+1]) and $F0 shr 4);
Result := Result + Alphabet[idx+1];
// 3rd char
if i+1 <= length(st) then
begin
idx := (ord(st[i+1]) and $F shl 2);
if i+2 <= length(st) then idx := idx + (ord(st[i+2]) and $C0 shr 6);
Result := Result + Alphabet[idx+1];
end
else
Result := Result + '=';
// 4th char
if i+2 <= length(st) then
begin
idx := (ord(st[i+2]) and $3F);
Result := Result + Alphabet[idx+1];
end
else
Result := Result + '=';
// next source char
Inc(i,3);
end;
end;

Thanks,

[LizR]

Dont re-invent the wheel. Download the function done by someone else

http://www.vbforums.com/showthread.php?t=379072

[poilkjmnb]

Dont re-invent the wheel. Download the function done by someone else

http://www.vbforums.com/showthread.php?t=379072

Thanks LizR.

but this encode string doesn't match the string which is return by delphi code.

[LizR]

hmm, it should as the encode64 function has a standard expectation.

Is the result even remotely similar?

[poilkjmnb]

hmm, it should as the encode64 function has a standard expectation.

Is the result even remotely similar?

Hello LizR,

when i m enter "pramod" as encode string in delphi code then it return me "NasK3DkF" after encoding.

[LizR]

and in vb 6? (something I dont have installed as I wouldnt use it by choice)

[arutya]

Form1.Image2.Picture:=Form1.Image1.Picture;
latar:=255;
obyek:=0;
setlength(ki,w,h);
setlength(kio,w,h);
for y:= 0 to hi do
begin
PC :=formutama.image1.picture.bitmap.scanline[y];
PH :=formutama.image2.picture.bitmap.ScanLine[y];
for x:=0 to wj do
begin
ki[x,y]:=PC[x];
kio[x,y]:=PH[x];
end;
end;

for x:= 1 to w-1 do
for y:= 1 to h-1 do
if(ki[x,y]=obyek) then
begin
kio[x-1,y]:=obyek;
kio[x+1,y]:=obyek;
kio[x,y-1]:=obyek;
kio[x,y+1]:=obyek;
end;

for y := 0 to hi do {tampil citra hasil}
begin
PH :=formutama.image2.picture.bitmap.ScanLine[y];
for x:= 0 to wj do PH[x]:=kio[x,y];
end;
ki:=nil;kio:=nil;

[arutya]

Form1.Image2.Picture:=Form1.Image1.Picture;
latar:=255;
obyek:=0;
setlength(ki,w,h);
setlength(kio,w,h);
for y:= 0 to hi do
begin
PC :=formutama.image1.picture.bitmap.scanline[y];
PH :=formutama.image2.picture.bitmap.ScanLine[y];
for x:=0 to wj do
begin
ki[x,y]:=PC[x];
kio[x,y]:=PH[x];
end;
end;

for x:= 1 to w-1 do
for y:= 1 to h-1 do
if(ki[x,y]=obyek) then
begin
kio[x-1,y]:=obyek;
kio[x+1,y]:=obyek;
kio[x,y-1]:=obyek;
kio[x,y+1]:=obyek;
end;

for y := 0 to hi do {tampil citra hasil}
begin
PH :=formutama.image2.picture.bitmap.ScanLine[y];
for x:= 0 to wj do PH[x]:=kio[x,y];
end;
ki:=nil;kio:=nil;

[CygnetInfo]

For converting Delphi to VB 6 you can download the complete information from Searching in Google.com regarding the conversion parameter.