Lost Again...Step Increment

[gh0sts416]

I Was Just Wondering is Ther Anyway At All
To Reproduce A VB Step Increment in Delphi.

VB Example:
for i = 0 to 100 step 10

Delphi: ???

Any Help Would Be A Blessing

Thanks,
gh0sts :)

[gh0sts416]

I Got It Figured Out :)

But Any Feed Back Would Still Be Appreciated.

[LizR]

Step is something that delphi kinda overlooked.

Easiest answer is a while loop.

[FlamingClaw]

Program increment_for;
Uses Crt;
Var i:Byte;

Begin
 ClrScr;
 For i:=0 To 100 Do
 Begin
  If i>=100 Then Break;
  Inc(i,20);                                   {increment i with 20}
  Write(i, '  ');
  Dec(i);                                       {decrement i with 1}
 End;

Repeat
Until KeyPressed;
End.

In the turbo pascal there is a function called INC(number,increment) and I think that the pascal was the base of the delphi

[LizR]

most languages dont like you messing with the itterator. You would do better to use a while loop.

[FlamingClaw]

I think you're right,the

While..Do

or the

Repeat..Until

can be the right way,'cause these statements are used for that....the point is yours...
With respect FlamingClaw

[FlamingClaw]

Ok,I know that this thread is not fresh but I have an idea,and working! :)

{
Question
Increment for loop
}
Program Program01;

var i:Byte;

Begin {main}
   For i:=1 To 100 Do
     Begin
       i:=i+9;  {will step 10}
       Write(i,' ');
     End;
   ReadLn;
End.

{
-= Note By FlamingClaw =-

All programs created by me  are written and tested
in Dev Pascal and/or Turbo Pascal 7.0

-= Created By FlamingClaw =-
-=2009.03.29=-
}

[jsosnowski]

FlamingClaw,
Two thoughts on your example:

1.) i := i + 9; // does not increment by 10
2.) Using the For statement could easily lead to an error in a large body of code. Imagine coming back to this a year from with no memery of the logic. You would see the For statement and assume an increment of 1 with the For statement controling the i variable. It would be better to use a With or Repeat statement because you would still seek out the increment line to evaluate the step size.

[FlamingClaw]

try it and you'll see that i:=i+9 will every round 10,cause when run this example you will see that every round value of i will increasing by 1....therefor nedd i:=i+9

[jsosnowski]

FlamingClaw,

My bad, you are right.

However, overiding the automatic increment still looks like a bad practice.