Postcode Validation

[WackyZ]

Can someone please help me - I need to write a function that will validate UK postcodes written in a textbox but every tutorial and example source code I find for it is in other languages such as VB and Javascript.

The VB code looks extremely small:

1.
Public Function isValidPostCode(ByVal input As String) As Boolean
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Dim validInput As Boolean = False
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' Check that the input is not null before checking
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If input IsNot Nothing Then
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' Regex from: http://www.cabinetoffice.gov.uk/media/291370/bs7666-v2-0-xsd-PostCodeType.htm
9.
validInput = Regex.IsMatch(input, "^(GIR 0AA)|((([A-Z-[QVX]][0-9][0-9]?)|(([A-Z-[QVX]][A-Z-[IJZ]][0-9][0-9]?)|(([A-Z-[QVX]][0-9][A-HJKSTUW])|([A-Z-[QVX]][A-Z-[IJZ]][0-9][ABEHMNPRVWXY])))) [0-9][A-Z-[CIKMOV]]{2})$", RegexOptions.IgnoreCase)
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End If
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Return validInput
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End Function

Is there a way this could be convereted for use in Delphi database?

[Ionelul]

I don't think that Delphi has any function to parse regular expressions, so I looked on this site http://www.ml-consult.co.uk/foxst-39.htm and found some informations from which i built the following function

function TForm1.CheckIfValid(anInput : String) : Boolean;
var
  iSpacePos, i : byte;
  sInward, sOutward : String;
begin
  Result := False;
  if (anInput = EmptyStr) then Exit;
  anInput := UpperCase(anInput);
  iSpacePos := Pos(' ', anInput);
  if iSpacePos = 0 then Exit;
  sInward := Copy(anInput, iSpacePos + 1, 3);
  sOutward := Copy(anInput, 1, iSpacePos - 1);

  if StrToIntDef(sInward[1], -1) = -1 then Exit;  //first char has to be a number
  //these characters never appear in the inward code
  if (AnsiIndexStr(sInward[2], ['C', 'I', 'K', 'M', 'O', 'V']) <> -1) or
    (AnsiIndexStr(sInward[3], ['C', 'I', 'K', 'M', 'O', 'V']) <> -1) then Exit;
//build the outward code as the patterns from the site
  for i := 1 to Length(sOutward) do
    if ord(sOutward[i]) in [65..90] then // or sOutward[i] in ['A'..'Z']
      sOutward[i] := 'A'
    else sOutward[i] := '9';

  if AnsiIndexStr(sOutward, ['A9', 'A99', 'AA9', 'A9A', 'AA99', 'AA9A']) = -1 then Exit;
//the code is valid, so i return true value
  Result := true;

end;

If you want to create a more accurate validation, read the entire article from the link I posted.

Ionut

[WackyZ]

Thank you so very much, you have really helped me a lot.

[Ionelul]

You're welcome, but you have found your answer, please mark the thread as solved.

Ionut