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Sep 18th, 2009

First attempt at raw_input

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So below is my first attempt at using user input, but I can't figure out how to get the input (at the bottom) to plug into my function definitions. I have no proper python training and am attempting to learn on my own with some books. I would appreciate any tips or suggestions.

Thanks!

python Syntax (Toggle Plain Text)
#!/usr/bin/python
 
def dispatch(choice):
	if choice == 'A':
		functionA()
	elif choice == 'B':
		functionB()
	elif choice == 'C':
		functionC()
	else:
		print "An Invalid Choice"
 
def functionA():
	print "WRONG!"
def functionB():
	print "CORRECT!"
def functionC():
	print "WRONG!"
 
choice = raw_input ("A, B, or C\n")
print "Your answer is", choice
#!/usr/bin/python

def dispatch(choice):
	if choice == 'A':
		functionA()
	elif choice == 'B':
		functionB()
	elif choice == 'C':
		functionC()
	else:
		print "An Invalid Choice"
		
def functionA():
	print "WRONG!"
def functionB():
	print "CORRECT!"
def functionC():
	print "WRONG!"
	
choice = raw_input ("A, B, or C\n")
print "Your answer is", choice

Last edited by optikali; Sep 18th, 2009 at 5:19 pm.

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optikali

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Sep 18th, 2009

Re: First attempt at raw_input

Try the appy(functionname, (args)) statement

(Toggle Plain Text)

def printit():
	print "hello, world!"

ch = input("enter a func->")

apply(ch, ())

Now at the prompt enter the function name printit and apply will execute it

Last edited by gerard4143; Sep 18th, 2009 at 5:32 pm.

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Sep 18th, 2009

Re: First attempt at raw_input

Simply call the dispatch(choice) function with your choice as argument:

python Syntax (Toggle Plain Text)
#!/usr/bin/python
 
def dispatch(choice):
    if choice == 'A':
        functionA()
    elif choice == 'B':
        functionB()
    elif choice == 'C':
        functionC()
    else:
        print "An Invalid Choice"
 
def functionA():
    print "WRONG!"
def functionB():
    print "CORRECT!"
def functionC():
    print "WRONG!"
 
choice = raw_input ("A, B, or C\n")
print "Your answer is", choice
# call the dispatch function with the argument in choice
dispatch(choice)
#!/usr/bin/python

def dispatch(choice):
    if choice == 'A':
        functionA()
    elif choice == 'B':
        functionB()
    elif choice == 'C':
        functionC()
    else:
        print "An Invalid Choice"
        
def functionA():
    print "WRONG!"
def functionB():
    print "CORRECT!"
def functionC():
    print "WRONG!"
    
choice = raw_input ("A, B, or C\n")
print "Your answer is", choice
# call the dispatch function with the argument in choice
dispatch(choice)

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Sep 18th, 2009

Re: First attempt at raw_input

Click to Expand / Collapse Quote originally posted by sneekula ...

Simply call the dispatch(choice) function with your choice as argument:
python Syntax (Toggle Plain Text)
#!/usr/bin/python
 
def dispatch(choice):
    if choice == 'A':
        functionA()
    elif choice == 'B':
        functionB()
    elif choice == 'C':
        functionC()
    else:
        print "An Invalid Choice"
 
def functionA():
    print "WRONG!"
def functionB():
    print "CORRECT!"
def functionC():
    print "WRONG!"
 
choice = raw_input ("A, B, or C\n")
print "Your answer is", choice
# call the dispatch function with the argument in choice
dispatch(choice)
#!/usr/bin/python def dispatch(choice): if choice == 'A': functionA() elif choice == 'B': functionB() elif choice == 'C': functionC() else: print "An Invalid Choice" def functionA(): print "WRONG!" def functionB(): print "CORRECT!" def functionC(): print "WRONG!" choice = raw_input ("A, B, or C\n") print "Your answer is", choice # call the dispatch function with the argument in choice dispatch(choice)

Worked like a charm!

Quick question, how can I easily make it so input is not case sensitive?

Thanks again!

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Sep 18th, 2009

Re: First attempt at raw_input

python Syntax (Toggle Plain Text)
# now all input strings/characters are upper case
choice = raw_input ("A, B, or C\n").upper()
# now all input strings/characters are upper case
choice = raw_input ("A, B, or C\n").upper()

Last edited by sneekula; Sep 18th, 2009 at 7:06 pm.

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Sep 18th, 2009

Re: First attempt at raw_input

You Rock! =D

optikali

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Sep 18th, 2009

Re: First attempt at raw_input

So I added questions and tried to make some efficiency tweaks, but why is "B" not being seen as the correct answer (e.g. it triggers functionWrong)?

Note: if I split the " 'A' or 'C' " into two if conditions it works fine =/

Thanks

python Syntax (Toggle Plain Text)
#!/usr/bin/python
 
def question():
	print "\n"
	print "What is the plural for Virus?\n"
	print "A. Virux"
	print "B. Viruses"
	print "C. Virus\n"
	choice = raw_input().upper()
	print "Your answer is", choice
	dispatch(choice)
 
def dispatch(choice):
	if choice == 'A' or 'C':
		functionWrong()
		question()
	elif choice == 'B':
		functionB()
		question()
	else:
		print "An Invalid Choice"
		question()
 
def functionWrong():
	print "WRONG!"
 
def functionB():
	print "CORRECT!"
 
question()
#!/usr/bin/python

def question():
	print "\n"
	print "What is the plural for Virus?\n"
	print "A. Virux"
	print "B. Viruses"
	print "C. Virus\n"
	choice = raw_input().upper()
	print "Your answer is", choice
	dispatch(choice)

def dispatch(choice):
	if choice == 'A' or 'C':
		functionWrong()
		question()
	elif choice == 'B':
		functionB()
		question()
	else:
		print "An Invalid Choice"
		question()
		
def functionWrong():
	print "WRONG!"

def functionB():
	print "CORRECT!"

question()

Last edited by optikali; Sep 18th, 2009 at 8:57 pm.

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Sep 19th, 2009

Re: First attempt at raw_input

if choice == 'A' or 'C':
is wrong, has to be
if choice == 'A' or choice == 'C':
or simpler
if choice in 'AC':

It looks like you are using tabs for indentations, stay away from those and use four spaces instead. Indentations are too important in Python to waste them on tab troubles.

Last edited by vegaseat; Sep 19th, 2009 at 12:26 am. Reason: no tabs!

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Sep 19th, 2009

Re: First attempt at raw_input

Click to Expand / Collapse Quote originally posted by vegaseat ...

if choice == 'A' or 'C':
is wrong, has to be
if choice == 'A' or choice == 'C':
or simpler
if choice in 'AC':

It looks like you are using tabs for indentations, stay away from those and use four spaces instead. Indentations are too important in Python to waste them on tab troubles.

Thanks so much! Oh and it's good to know about tabbing, I should stop now before it becomes habit.

I think now that I'm getting these down my first big project will be a choose your own adventure game!

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Sep 19th, 2009

Re: First attempt at raw_input

As you start coding larger projects with Python, remember to go in small steps, test each step, ask question here. Python can be fun!

Python is in many ways more advanced and modern than some of the old stale standby languages like Basic, C, C++, C# and Java. There is a lot of power under that hood, so drive responsibly.

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