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Sep 20th, 2009

Displaying Deck of Cards

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I am currently learning Python and how to work with start and stop indexing. I am doing a project from the book I am learning from and I'm stumped...I need to display a full deck of cards, with

Python Syntax (Toggle Plain Text)
numbers = ("A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K")
suits = ("c", "h", "s", "d")
numbers = ("A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K")
suits = ("c", "h", "s", "d")

so that it displays the entire deck, paired and ordered to look like:

Ac Ah As Ad
2c 2h 2s 2d
3c 3h 3s 3d
.
.
.
.
Qc Qh Qs Qd
Kc Kh Ks Kd

so far all I have are the numbers and suits set up but I keep trying to do things way too complicated with for loops, so i completely deleted my code and came here for fresh ideas.

Thanks

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etypaldo

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Sep 20th, 2009

Re: Displaying Deck of Cards

One way is like this
Take numbers and add like this "A" count as 1.

python Syntax (Toggle Plain Text)
>>> numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] + 'Jack Queen King'.split()
>>> numbers
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 'Jack', 'Queen', 'King']
>>> 
>>> suits = ['diamonds', 'clubs', 'hearts', 'spades']
>>> suits
['diamonds', 'clubs', 'hearts', 'spades']
 
>>> deck = ['%s of %s' % (n, s) for n in numbers for s in suits]
>>> deck
# the hole deck
 
And we can make it look better.
>>> from pprint import pprint
>>> pprint(deck[:10])  #52 gives the hole deck
['1 of diamonds',
 '1 of clubs',
 '1 of hearts',
 '1 of spades',
 '2 of diamonds',
 '2 of clubs',
 '2 of hearts',
 '2 of spades',
 '3 of diamonds',
 '3 of clubs']
>>>
>>> numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] + 'Jack Queen King'.split()
>>> numbers
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 'Jack', 'Queen', 'King']
>>> 
>>> suits = ['diamonds', 'clubs', 'hearts', 'spades']
>>> suits
['diamonds', 'clubs', 'hearts', 'spades']

>>> deck = ['%s of %s' % (n, s) for n in numbers for s in suits]
>>> deck
# the hole deck

And we can make it look better.
>>> from pprint import pprint
>>> pprint(deck[:10])  #52 gives the hole deck
['1 of diamonds',
 '1 of clubs',
 '1 of hearts',
 '1 of spades',
 '2 of diamonds',
 '2 of clubs',
 '2 of hearts',
 '2 of spades',
 '3 of diamonds',
 '3 of clubs']
>>>

snippsat

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Sep 20th, 2009

Re: Displaying Deck of Cards

I am not sure which version of Python you are using, but if you explore this code ...

python Syntax (Toggle Plain Text)
rank = ("A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K")
suit = ("c", "h", "s", "d")
 
deck = []
for r in rank:
    for s in suit:
        card = r + s
        deck.append(card)
 
print( deck )
rank = ("A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K")
suit = ("c", "h", "s", "d")

deck = []
for r in rank:
    for s in suit:
        card = r + s
        deck.append(card)

print( deck )

... you can see the the list called deck is almost ordered the way you want it. All you need to do now is to print four of the list's elements in a row and then slip in a newline character. Put your thinking hat on!

vegaseat

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DaniWeb's Hypocrite

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Sep 21st, 2009

Re: Displaying Deck of Cards

Just to explain one thing look at vegaseat code.
Does it look like this line?

Python Syntax (Toggle Plain Text)
deck = ['%s of %s' % (n, s) for n in numbers for s in suits]
deck = ['%s of %s' % (n, s) for n in numbers for s in suits]

This is called list List Comprehensions
I can wite it like this.

Python Syntax (Toggle Plain Text)
deck = []
for n in numbers:
    for s in suits:
        card = '%s of %s' % (s, n)
        deck.append(card)
deck = []
for n in numbers:
    for s in suits:
        card = '%s of %s' % (s, n)
        deck.append(card)

Then you see it not so differnt.

snippsat

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Sep 21st, 2009

Re: Displaying Deck of Cards

As a beginner use for loops first, later on 'list comprehensions' become more natural.

sneekula

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