Could you be more clear on the conditions you want met?

I have written 2 functions already, they are:

def sum1(n):
result = n * (n + 1) / 2
print result

def sum2(n):
sum = 0
for x in range(1,n+1):
sum = x + sum
print sum

And this what I need to do for the third function:

The third function (call it "sum3") computes and prints the answer using a "while" loop. In some respects the code is similar to the "for" loop of part 2 above. However, unlike a "for" loop, you have to initialize a counting variable, test to see if it is small enough (using the while loop) and if so, execute the loop body. In the body you must increment the counting variable. This function is about 6 lines long.

well I think you answered the question you know how to create the while loop here's a hint:


Hope this helps

Im not really sure what your computing or what you need in the body but the while loop and the increment should be what your looking for.

We can't really do your homework for you, but the basics of a while loop are like this.

So initially some_flag does not meet the desired condition. The loop continually updates the value of some_flag , and when it finally meets the condition that you specify, the loop automatically breaks.

You could alternately simply do a while True: loop (super loop or infinite loop), and then compare the flag to a condition using an if statement. If the flag meets the condition, use break to break out of the super loop.

Thanks everybody for your help, I figured it out and got it to do what I wanted.

Congratulations!