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URL filter

I want to create a system to filtering a URL in python

hungryforwork.co.nz/company/job/

eg

hungryforwork.co.nz/telecom/5/

I want to put out the telecom and lookup this company and then 5 for a reference to a listed job

Putting a folder for each company would be a mission.

An error 404 might work

Does someone have an answer

Bevosnz
Newbie Poster
1 post since Apr 2011
Reputation Points: 10
Solved Threads: 0
 

Post some code using the [CODE] button, and ask for help making it work better. Using better or more careful English.

griswolf
Veteran Poster
1,165 posts since Apr 2010
Reputation Points: 344
Solved Threads: 256
 

Let see what you have done, in terms of code, and then the errors you got if any. Then we will pick it from there, i can't really decode all you've said.

e-papa
Posting Pro in Training
465 posts since Mar 2011
Reputation Points: 23
Solved Threads: 4
 

This question has already been solved

Post: Markdown Syntax: Formatting Help
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