Result Sorter issues

[e-papa]

I've tried to make a program that will sort the results of a competition, by asking the user the number of competitors, then the name and score of each one.
It worked but now i have to make it recognize when two or more people get the same score (that is) they have the same position, and that the number of extra people on a position will be the number of position that will be omitted before it continues ranking the others. Here is what i have done, so far,

# Filename: result_sorter.py
# A Program that's sorts results
#
# Obasa Adegoke - 18/04/11(dd/mm/yy)



# This function allows the user to quit at any time in the program
def quitter(word):
    """ Allows the user to quit at any time"""

    if word.upper() == "Q":
        quit()
    else:
        pass

def result_sorter():
    play_again = 'yes'
    while play_again == 'yes' or play_again == 'y':
        # This line asks the user for the number of values
        count = input("Number")
        quitter(count)
        count = int(count)

        # Initialize the various lists to be used
        name = []
        score = []
        sorting = []
        # The Various names and respective scores are added to the lists
        for i in range(count):
            # this line accepts the name
            temp1 = input("name")
            quitter(temp1)
            temp1 = str(temp1.title())
            name.append(temp1)

            # this line accepts the respective score
            temp2 = input("score")
            quitter(temp2)
            temp2 = int(temp2)
            score.append(temp2)
            sorting.append(temp2)

        # Scores are sorted in ascending order
        sorting.sort()

        print("\t Postion \t Name \t \t Score")
        n = 1
        k = count
        while n!= count +1:
            rank = sorting.pop(0)
            index = int(score.index(rank))
            name_sort = name[index]
            print('\t {0} \t \t \t {1} \t \t {2}'.format(k, name_sort, rank))
            n += 1
            k -= 1

        play_again = input("Do you want to sort again [y or n]")
        play_again = play_again.lower()


print(" Result Sorter ".center(40, '*').center(70))
print(" version 1.0 ".center(40, '*').center(70))
print('To quit at anytime just type [q]'.center(70))
result_sorter()
print("copyright 2011".center(70))

Will love to know how i can make it do this, and also how i can make it print from top to bottom instead of bottom to top.
Thanks in advance.

[woooee]

To associate name and score you would use a list, tuple or dictionary of pairs, so as to keep them together. The name and score that you print do not necessarily go together. The Python sorting HowTo is here .

import operator

name_score = []

## example data
name = "Joe"
score = 5 
name_score.append([name, score])

name = 'Steve'
score = 2
name_score.append([name, score])

name = 'Mike'
score = 7
name_score.append([name, score])

print name_score

name_score.sort()   ## in name order
print "\nname order", name_score

## itemgetter[1] = memory offset X 1 = second item = score
score_sorted = sorted(name_score, key=operator.itemgetter(1))
print "\nscore order", score_sorted

[e-papa]

Thanks woooee
Will try to read more on the operator module, thanks again.

[e-papa]

I'm sorry I forgot something, how about when i want to add positions, and two or more persons have the same scores, how do i go about doing things like that, i still trying to work on that.

Well this is what i now have, thanks for the help

# Filename: result_sorter.py
# A Program that's sorts results
#
# Obasa Adegoke - 18/04/11(dd/mm/yy)


import operator


# This function allows the user to quit at any time in the program
def quitter(word):
    """ Allows the user to quit at any time"""

    if word.upper() == "Q":
        quit()
    else:
        pass

def result_sorter():
    play_again = 'yes'
    while play_again == 'yes' or play_again == 'y':
        # This line asks the user for the number of values
        count = input("Number\n".center(70))
        quitter(count)
        count = int(count)
        # Initialize the various list to be used
        name_score = []
        # The Various names and respective scores are added to the lists
        for i in range(count):
            # this line accepts the name
            name = input("Competitor\n".center(70))
            quitter(name)
            name = str(name.title())
            # this line accepts the respective score
            score = input("Competitor's score\n".center(70))
            quitter(score)
            score = int(score)
            name_score.append([name, score])

        # results in raw form
        print("|                                |".center(70))
        print("Results".center(40).center(70))
        for i in name_score:
            print('{0}'.format(i).center(40).center(70))

        # results sorted
        name_score.sort()

        # results in name order
        print("|                                |".center(70))
        print("Results sorted in name order".center(40).center(70))
        for i in name_score:
            print('{0}'.format(i).center(40).center(70))
            print('-'.center(20, '-').center(70))

        score_sorted = sorted(name_score, key = operator.itemgetter(1))

        # results in rank order
        print("|                                |".center(70))
        print("Ranked results".center(40).center(70))
        for i in score_sorted:
            print('{0}'.format(i).center(40).center(70))

        play_again = input("Do you want to sort again [y or n]")
        play_again = play_again.lower()

# start program
print("+--------------------------------+".center(70))
print("|       Result Sorter v1.0       |".center(40).center(70))
print("+--------------------------------+".center(70))
print('|To quit at anytime just type [q]|'.center(70))
result_sorter()
print("|                                |".center(70))
print("|         copyright 2011         |".center(70))
print("+--------------------------------+".center(70))

how did I do.

[griswolf]

You could use itertools.groupby which has a nice example right in the docs.
Once you have the groups, just calculate the ranking: All the folks in the first group tie for 1st place. All the folks in the second group tie for (count of 1st-place people + 1); All in the Nth group tie for place (sum of people in previous groups)+1

[pyTony]

Or you can keep the original, sorted by points list and record the points where number of points change + 1 (or enumerate starting from 1) as position for that many points in dictionary.

import random

COUNT = 20
MAXPOINTS = 12

points = [random.randint(1, MAXPOINTS) for count in range(COUNT)]
print('Points unsorted', points)
points_sorted = sorted(points, reverse = True)
print('Points sorted', points_sorted)

positions = dict()
prev = float('inf')

for place, p in enumerate(points_sorted, 1):
    if prev > p:
        positions[p] = place
    prev=p
    
for player_no, p in enumerate(points, 1):
    print('Player %i, points %i, position %i' %(player_no, p, positions[p]))

[e-papa]

You could use itertools.groupby which has a nice example right in the docs. Once you have the groups, just calculate the ranking: All the folks in the first group tie for 1st place. All the folks in the second group tie for (count of 1st-place people + 1); All in the Nth group tie for place (sum of people in previous groups)+1

itertools seems to be very good,I'll check it out, thanks a lot.

[e-papa]

Or you can keep the original, sorted by points list and record the points where number of points change + 1 (or enumerate starting from 1) as position for that many points in dictionary.

import random

COUNT = 20
MAXPOINTS = 12

points = [random.randint(1, MAXPOINTS) for count in range(COUNT)]
print('Points unsorted', points)
points_sorted = sorted(points, reverse = True)
print('Points sorted', points_sorted)

positions = dict()
prev = float('inf')

for place, p in enumerate(points_sorted, 1):
    if prev > p:
        positions[p] = place
    prev=p
    
for player_no, p in enumerate(points, 1):
    print('Player %i, points %i, position %i' %(player_no, p, positions[p]))

Thanks a lot, i will try and read through this understand and implement, thanks again for the help.