Hi,
I wish to delete the last three lines of a file iteratively. I tried this in unix shell scripting but it is not working..
lines=$(wc -l < s27.cnf) target=$((lines-2)) sed '$target,$lines d' s27.cnf > f2.cnf mv f2.cnf s27.cnf
I am getting an error "sed: 1: "$target,$lines d": undefined label 'arget,$lines d' So was not sure what to use.
I would appreciate help on this.
Single quotes disable substitution, so perhaps sed "$target,$lines d" s27.cnf > f2.cnf sed $target','$lines' d' s27.cnf > f2.cnf
sed "$target,$lines d" s27.cnf > f2.cnf sed $target','$lines' d' s27.cnf > f2.cnf
Hey there,
You can also do it this way
sed -e :a -e '$d;N;2,3ba' -e 'P;D' s27.cnf >f2.cnf
Just change the 3 to hower many lines you want to delete from the bottom
Best wishes,
Mike
Thanks...it worked...
I appreciate the help
Your welcome, of course :)