Hi all.
I am trying to write a "light" version of srm just as an exercise of shell scripting (started today with this ^^" I have to keep it
really simple)
Basically it should just search for a file and, if found, ask for a confirmation before deleting it.
Now, it worked fine with /any/directory/you/like/no_spaces_in_the_name.file and I hoped to make it a little less dumb
Here's the code:
#!/bin/bash
#
#Script to safely remove files (asks confirmation)
#
choice="n"
if [ $# -eq 0 ]
then
echo "srm: missing argument."
echo "Syntax: $0 file_to_safely_delete."
exit 1
fi
filename=$1
if [ $# -gt 1 ]
then
filename="'$@'"
echo "$filename"
fi
if test -f $filename
then
echo "$filename found. Are you sure you want to permanently delete it? (y/n)"
read choice
if [ $choice = "y" ]
then
`rm $filename`
echo "$filename permanently deleted."
else
echo "$filename untouched."
fi
else
echo "$filename not found. Nothing done."
fi
The added part is
if [ $# -gt 1 ]
then
filename="'$@'"
echo "$filename"
fi
I put in it
echo "$filename" for debugging and it shows correctly the string
'name of file with spaces'
The error I receive is @ this line:
if test -f $filename
It prints out this:
line 18: test: too many arguments After I call it with
srm just a try
I am just blind on why it doesn't work... any idea?
Anticipate thanks
p.s.
I have not yet find anything abount problems with spacing in shell scripting, but ¿strangely? if I indent the code like I'm used to with c/c++ it complains a lot so I'm not doing it at all. It's not urgent but I think I'm simply missing something obvious, so I'll be very grateful to anyone who'll give a sort of explanation ^^"
p.p.s.
as usual sorry for my english
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