Shell program to find GCD

[man5237]

Please help me to write a shell script to find the GCD (Greatest common Divisor) of 3 numbers.

Thanks in advance.

[Salem]

Why are you trying to do maths in the shell (which it really isn't set up to do).

[man5237]

Project work

[man5237]

I got a program to find the GCD of 2 numbers. But i need the program to find the GCD of three numbers.

Program to find the GCD of 2 numbers is as follows

echo "Enter first number" read n1 echo "Enter the second number" read n2 gcd=0 if test $n1 -gt $n2 then i=1 while test $i -le $n1 do a=`expr $n1 % $i` b=`expr $n2 % $i` if test $a -eq 0 -a $b -eq 0 then if test $gcd -lt $i then gcd=$i fi fi i=`expr $i + 1` done fi if test $n2 -gt $n1 then i=1 while test $i -le $n2 do a=`expr $n1 % $i` b=`expr $n2 % $i` if test $a -eq 0 -a $b -eq 0 then if test $gcd -lt $i then gcd=$i fi fi i=`expr $i + 1` done fi echo GCD of $n1 and $n2 = $gcd

So please write a program to find the GCD of 3 numbers.

[Salem]

Isn't that just gcd(a,gcd(b,c))

> So please write a program to find the GCD of 3 numbers.
No, we suggest, you do it.

My suggestion is you look to see if your shell supports functions, which you can call in the manner I've described.

[man5237]

I tried but I am unable to write the program.

So please write the whole program for me.

Please.

[Salem]

So did you do ANY research on how to write a function in shell?
Did you try a few examples to see how it might work for you?

[kvmreddy]

check this link GCD of more than two numbers