Problem printing date

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I have declared a variable:
today=$(date +%m/%d/%Y)
and I am trying to use sed to replace the word "in" with "out:date:name" but don't know the correct syntax to make $today print correctly. I have tried quotes and double quotes and brackets but to no avail. When I do it like this, $name prints correctly, but $today prints literally "$today"
sed 's/\<in\>/out:'$today':'$name'/'

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Mattpd

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Nov 6th, 2009

Re: Problem printing date

sed 's_in_out:'$today':'$name'_'

versatileint

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