well i tried n it didn work.. wher shud i write tht code line??
arjunsasidharan
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826 posts since Aug 2006
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i guess you can do that in the form_load event.
Call the button in the load event
button1.image = (the path where you have the image of the button or place it in the bin)
arjunsasidharan
Practically a Posting Shark
826 posts since Aug 2006
Reputation Points: 347
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place the
conn.Open() under the Try - Catch.. it will work
arjunsasidharan
Practically a Posting Shark
826 posts since Aug 2006
Reputation Points: 347
Solved Threads: 13