sql commad problem
In a data environment I write code like:
select ([exam fee]*[other fee]) as total from table1
then it work, but when I write like below it not work:
select sum[exam fee] as total from table1
what problem with it?
abu taher
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How does it not work?
and should that not be ([exam fee] + [other fee])
Good Luck
vb5prgrmr
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another thing. I write like:
"select sum[exam fee] as total , sum[other fee] as total_fee from table1"
it not work
abu taher
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Are the fields numeric? If not that could be your problem but without seeing your code who knows.
Good Luck
vb5prgrmr
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ya that field are numeric.
abu taher
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NOTE:
sum[exam fee] ==> sum([exam fee])
Mbt925
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NOTE:
sum[exam fee] ==> sum([exam fee])
I don't understand by this code. I want sum[exam fee] and sum[other fee]. is it possible with your code?
abu taher
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I don't understand by this code. I want sum[exam fee] and sum[other fee]. is it possible with your code?
yes.
SUM is a sql function. you must use '(' & ')' for it.
change your code in this way:
"select sum<strong>(</strong>[exam fee]<strong>)</strong> as total , sum<strong>(</strong>[other fee]<strong>)</strong> as total_fee from table1"
Mbt925
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thanks Mtb 925. it works well. another thing when I input exam fee in a form and when I see the report it not update. I mean exam fee is 200 and I add again 200. so report will show 400/ but it show 200, when I exit and again open the project then show 400. please help me
abu taher
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thanks Mtb 925. it works well. another thing when I input exam fee in a form and when I see the report it not update. I mean exam fee is 200 and I add again 200. so report will show 400/ but it show 200, when I exit and again open the project then show 400. please help me
Your welcome.
you must reconnect it. attach your sample. i will edit it.
Mbt925
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you must reconnect it
reconnect mean......................
abu taher
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you must reconnect it
reconnect mean......................
reconnect meanattach your code. :icon_wink:
Mbt925
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try refreshing your connection.....ADO ....RDO whatever u r using
dspnhn
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