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Oct 21st, 2008
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new to xslt

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Hi guys,
Im brand new to doing tansformations and cannot seem to wrap my head around it.
I have a Xml File which looks something like
XML, XSLT and XPATH Syntax (Toggle Plain Text)
  1. <parentNode>
  2.   <childnode1 att1="1" att2="2"/>
  3.   <childnode2></childnode2>
  4.   <childnode1 att1="1" att2="2"/>
  5.   <childnode21></childnode21>
  6.   <childnode1 att1="1" att2="2"/>
  7.   <childnode22></childnode22>
  8.   <childnode1 att1="1" att2="2"/>
  9.   <childnode23></childnode23>
  10.   <childnode1 att1="1" att2="2"/>
  11.   <childnode24></childnode24>
  12.   <optionalNode></optionalNode>
  13. </parentNode>

The childnode labled ChildNode1 is repeated several times (the values are identical) and what i am trying to do is transform this xml into a new xml which only has one childnode1
and teh rest are "deleted" or ignored during the transformation.Everything else must stay the same and the position of the childnode needs to be the first position it is found in.
I know the name of the childNode1 before hand.
XML, XSLT and XPATH Syntax (Toggle Plain Text)
  1. <parentNode>
  2.   <childnode1 att1="1" att2="2"/>
  3.   <childnode2></childnode2>
  4.   <childnode21></childnode21>
  5.   <childnode22></childnode22>
  6.   <childnode23></childnode23>
  7.   <childnode24></childnode24>
  8.   <optionalNode></optionalNode>
  9. </parentNode>
Is this even possible?
How should i go about it.
Thank you
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Light Poster
nnobakht is offline Offline
47 posts
since Nov 2006
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Oct 27th, 2008
0

Re: new to xslt

Here is an XSLT that will do what you want.

XML, XSLT and XPATH Syntax (Toggle Plain Text)
  1. <?xml version="1.0" encoding="UTF-8"?>
  2. <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  3. 	<xsl:output method="xml" indent="yes"/>
  4.  
  5.     <xsl:template match="/">
  6.     	<parentNode>
  7. 	    	<xsl:copy-of select=".//childnode1[1]"/>
  8.  
  9. 	    	<xsl:for-each select="./parentNode/child::*[not(name()='childnode1')]">
  10. 	    		<xsl:copy-of select="."/>
  11. 	    	</xsl:for-each>
  12. 	    </parentNode>
  13. 	</xsl:template>
  14.  
  15. </xsl:stylesheet>

At the root we create the <parentNode> that will contain all children. Since we only want one childnode1, we copy the first by using the "[1]" position argument. We then loop through all of the children of parentNode, copying only those that are not named childnode1.
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gravyboat is offline Offline
14 posts
since Jun 2008
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Oct 28th, 2008
0

Re: new to xslt

Thank you. This really Helped.
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Solved Threads: 1
Light Poster
nnobakht is offline Offline
47 posts
since Nov 2006

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