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Views: 451 | Replies: 2 | Solved
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Join Date: Nov 2007
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Junior Poster
I try to simply concat the arguments if they are not the same..... what is wrong with this simple code for concat???
if i run it :
$ ./foo a b c
./foo: a=a b: not found
./foo: a=a c: not found
a
why a=a b: not found??? where this came from???
#!/bin/sh
result=$1
shift
while [ "$#" -ne "0" ]
do
next=$1
if [ $result = $next ]
then
:
else
$result="$result $next"
fi
shift
done
echo "$result"if i run it :
$ ./foo a b c
./foo: a=a b: not found
./foo: a=a c: not found
a
why a=a b: not found??? where this came from???
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Join Date: Dec 2005
Posts: 3,834
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> $result="$result $next"
Remove the first $ perhaps?
Like your other assignment earlier on.
Remove the first $ perhaps?
Like your other assignment earlier on.
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Join Date: Apr 2008
Posts: 44
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Solved Threads: 8
Light Poster
The above from Salem's post needs to be done to fix your issue.. but you may also want to fix your if statement.
The data in these variables are strings and need to be compared as such.
It probably isn't necessary, but you may want to say:
if [ "$result" = "$next" ]
The data in these variables are strings and need to be compared as such.
It probably isn't necessary, but you may want to say:
if [ "${result}" = "${next}" ] |
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