please take a look at my question

•

What is DaniWeb IT Discussion Community?

You're currently browsing the Shell Scripting section within the Software Development category of DaniWeb, a massive community of 403,512 software developers, web developers, Internet marketers, and tech gurus who are all enthusiastic about making contacts, networking, and learning from each other. In fact, there are 4,113 IT professionals currently interacting right now! Registration is free, only takes a minute and lets you enjoy all of the interactive features of the site.

Join our community!

Please support our Shell Scripting advertiser: Programming Forums

Thread Tools Display Modes

Views: 377 | Replies: 1

•

Join Date: Nov 2007

Posts: 108

Reputation: k2k is an unknown quantity at this point

Rep Power: 1

Solved Threads: 0

k2k

Offline

Junior Poster

please take a look at my question

Jun 28th, 2008

The code "named mywhich" below does basically the same thing as the "which" command in sh does. however, if i do >mywhich wrongcmd wrongcmd2 wrongcmd3

it will only returns wrongcmd3 not found ...... how do i make it like:
wrongcmd not found
wrongcmd2 not found
wrongcmd3 not found ???

I really wanna know this... any one can point out how will be highly appreciated. thank you

Help with Code Tags

(Toggle Plain Text)

#!/bin/sh

all=FALSE


while getopts a option
do
  case "$option" in
       a) all=TRUE;;
      \?) echo "Usage: mywhich [-a] command"
          exit 1;;
  esac
done

if [ "$OPTIND" -gt "$#" ]
then
    echo "error: missing command name!"
    found=0
fi

if [ "$all" = TRUE ]
then
    shift                             #trash the -a and make command to $1
#!/bin/sh
#90.312 Programming Assignment1
#Henry Li

all=FALSE


while getopts a option
do
  case "$option" in
       a) all=TRUE;;
      \?) echo "Usage: mywhich [-a] command"
          exit 1;;
  esac
done

if [ "$OPTIND" -gt "$#" ]
then
    echo "error: missing command name!"
    found=0
fi

if [ "$all" = TRUE ]
then
    shift                             #trash the -a and make command to $1
    while [ "$#" -ne "0" ]
    do

      command=$1                       #first command being at $1
      for dir in `echo $PATH | sed 's/:/ /g'`
      do
        if [ -x "$dir/$command" ]
        then
          found=0
          echo "$dir/$command"         #if command is -x, then echo it with path
          else
          badcommand=$command

        fi
      done
    shift                              #shift second command to $1
    done


else                          #if all=FALSE
    while [ "$#" -ne "0" ]
    do
        command=$1
        for dir in `echo $PATH | sed 's/:/ /g'`
        do
           if [ -x "$dir/$command" ]
           then
               found=0
               echo "$dir/$command"
               break
           else

               badcommand=$command
           fi
        done
    shift                     #shift the 2nd command to $1
    done
fi

if [ "$found" != 0 ]
then
   echo "$badcommand is not found"
fi

•

Join Date: Apr 2008

Posts: 39

Reputation: omrsafetyo is an unknown quantity at this point

Rep Power: 1

Solved Threads: 8

omrsafetyo omrsafetyo is offline

Offline

Light Poster

Re: please take a look at my question

Jul 1st, 2008

You are only returning (echoing) the last iteration of badcommand. Your while/for/if loop above assigns the current argument that it is processing to the badcommand variable. You let that loop run through all arguments and THEN exit out of the loop and echo. It's only echoing the last command it processed as "not found".

You need to move your echo into your else statement.