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Join Date: May 2005
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I have two files containing users, but the lists differ. My goal is to take all the users in file1 and remove them from file2. What would be a simple method for completing this?
-moktod
-moktod
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I have no idea how you would do that in Shell Scripting. I could do it in Perl fairly easily... but I think that might be a little bit of a task in Shell.
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I should be able to iterate through file1 and say if a match is found in file2, do some sed removal of that line, right? I suppose I would need the correct sed command.
-moktod
-moktod
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Originally Posted by Comatose
I have no idea how you would do that in Shell Scripting. I could do it in Perl fairly easily... but I think that might be a little bit of a task in Shell.
How would you accomplish this in perl?
-moktod
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Sure, you could do that. It just seems like it would be more work in my opinion. Here is the link a sed man page: http://www.rt.com/man/sed.1.html, and a sed tutorial: http://www.selectorweb.com/sed_tutorial.html, and here is info on reading files in Bash: http://www.linuxgazette.com/node/8384.
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Well, This isn't the perl forum, so I probably shouldn't have posted that in here (my apologies). In Either language, though, I would read the first file, and compare it to each line of the second file. In perl, I'd read both into arrays, loop through and compare the arrays.
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Attached Is How I would do this with a Perl Script. I'm working on doing it in bash shell right now also... but it seems a bit more complicated to me.... maybe I just like the feel of perl better, and so it flows more naturally and easy to me... but I'll keep giving it a go in Shell.
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Originally Posted by moktod
I have two files containing users, but the lists differ. My goal is to take all the users in file1 and remove them from file2. What would be a simple method for completing this?
-moktod
look into 'man comm'
vlad
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