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Join Date: Dec 2007
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Newbie Poster
I need a shell script to simultaneously run multiple instances of a compiled c code
can some one please help i'm using BASH
can some one please help i'm using BASH
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Join Date: Oct 2007
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Posting Whiz
One way to do it, also assuming know how many instances of it you want to run, is in a loop, start the process in the background.
while (x < counter){
./process&
x++;
} Last edited by stilllearning : Dec 4th, 2007 at 10:57 am.
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Newbie Poster
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Originally Posted by stilllearning 
One way to do it, also assuming know how many instances of it you want to run, is in a loop, start the process in the background.
while (x < counter){ ./process& x++; }
thanks for that
but the code is giving an error
./runall.sh: line 7: syntax error: unexpected end of file
#!/bin/bash
while (x < 101)
{
./<filename> &
x++;
} •
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Join Date: Oct 2007
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Posting Whiz
Change this
To this and you should be good
The bash tutorial referenced in a previous post is a good read if you're going to be doing this a lot. There are more succinct ways of getting this done using bash's built-ins, but, I'm an old dog
Best wishes,
, Mike
#!/bin/bash
while (x < 101)
{
./<filename> &
x++;
}To this and you should be good
#!/bin/bash
x=1
while [ $x -lt 101]
do
./filename &
let x=$x+1
doneThe bash tutorial referenced in a previous post is a good read if you're going to be doing this a lot. There are more succinct ways of getting this done using bash's built-ins, but, I'm an old dog
Best wishes,
, Mike
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