Unable to get the Open property of the Workbooks class

[PotaZinga]

Hi everyone i am getting an error that says Microsoft Office Excel error '800a03ec'
Unable to get the Open property of the Workbooks class when i try to open an excel work book in my code . The line of code where i get the error is Set ExcelBook = ExcelApp.Workbooks.open(BookPath) where BookPath is the path to the file .
The code before the line where the error is looks like this
Set ExcelApp = CreateObject("Excel.Application")
ExcelApp.Application.Visible = false
BookPath = "c:\filename.xls"
Set ExcelBook = ExcelApp.Workbooks.open(BookPath)

please help and thank you in advance

[PotaZinga]

hi!

here is a solution that worked for me .

・Windows 2008 Server x64

Please make this folder.

C:\Windows\SysWOW64\config\systemprofile\Desktop

・Windows 2008 Server x86

Please make this folder.

C:\Windows\System32\config\systemprofile\Desktop

and do not forget to give relevant rights to those folders .

http://social.msdn.microsoft.com/Forums/en-US/innovateonoffice/thread/b81a3c4e-62db-488b-af06-44421818ef91?prof=require