Generate the auto generate number with current month and year. Its Should auto generate. Thanks in advance
gpriya govind
0
Newbie Poster
Recommended Answers
Jump to PostNot sure what you are looking for exactly but maybe this will help you.
Dim RandomClass As New Random() Dim RandomNumber As Integer Dim strStringPart As String = Month(Now).ToString & Year(Now).ToString Dim NewRandomNumber As Integer RandomNumber = RandomClass.Next(1000, 9999) NewRandomNumber = Int32.Parse(strStringPart & RandomNumber) 'NewRandomNumber contains 220135765 …
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hometownnerd
13
Newbie Poster
Not sure what you are looking for exactly but maybe this will help you.
Dim RandomClass As New Random()
Dim RandomNumber As Integer
Dim strStringPart As String = Month(Now).ToString & Year(Now).ToString
Dim NewRandomNumber As Integer
RandomNumber = RandomClass.Next(1000, 9999)
NewRandomNumber = Int32.Parse(strStringPart & RandomNumber)
'NewRandomNumber contains 220135765 which is month, 4 digit year, and random number between 1000 and 9999
hope that helps or gets you in the right direction.
Larry
JorgeM
958
Problem Solver
Team Colleague
Featured Poster
auto generate number with current month and year. Its Should auto generate.
If you can be more specific and/or clarify what you are having trouble with, that would be helpful in getting the best guidance.
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