help

[lydia21]

hi,
i want to develop a application....
where the user can enter the no of text boxes he wants..in the next page based on the user input it should disply the text boxes with different id

[nav33n]

Say, for example, the user enters 10 in the first screen. On the next screen, you can do something like,

$textboxes_number=$_POST['number']; //the number of textboxes the user wants
$textboxes_number=10; //say user enters 10 in the previous screen
echo "<form name=form method=post action=somepage.php>";
for($i=0;$i<$textboxes_number;$i++){
echo "<input type='text' name=txt$i>";
}

echo "<input type='submit' name='submit' value='submit'>";
echo "</form>";

This will generate 10 textboxes with different names.

Cheers,
Naveen

[fatihpiristine]

use javascript,
when the user enters data into first textbox, add there automatically another textbox n name it text02, keep this process and on post just catch the data. thats all.

[lydia21]

thanks it worked..........
test3.php

<?php
$tboxes=$_REQUEST['tboxes'];
echo $tboxes;
if (isset($_REQUEST['Submit']))
{
for ($i = 0; $i < $tboxes; $i++)
{
print "";
}
print "";
}
?>

next page to process further(test3.php)
<?php
if (isset($_REQUEST['Submit']))
{
for ($i = 0; $i < 5; $i++)
{
$i=$_REQUEST['i']:
echo $i;
}
}
}
?>

please do tell me how to get the values entered in the text boxes to the next page

[nav33n]

Have a hidden field to pass the number of textboxes. In the next page, use a for loop to get the values entered in those textboxes.

for($i=0;$<$number_of_textboxes;$i++){
 $txtboxname=$txt.$i;
$textbox_value=$_POST[$txtboxname];
print $textbox_value;
}

:)

[lydia21]

textbox value is not getting printed

[nav33n]

code ?

[rudevils]

try it like this

for($i=0;$<$number_of_textboxes;$i++){
$txtboxname = $txt.$i;
$textbox_value .= $_POST[$txtboxname] ;
$textbox_value .= "
"; //one value per line
}
echo $textbox_value;

hope it works

[kings]

hi
i tried both the below codes.
it is displaying the text box id,but not the user input

if (isset($_REQUEST['Submit']))
{
echo $_SESSION[tboxes];
for($i=0;$i < $_SESSION[tboxes];$i++)
{
$txtboxname=$txt.$i;
echo $txtboxname;
$textbox_value=$_REQUEST[$txtboxname];
echo $textbox_value;
}
}

for($i=0;$i < $_SESSION[tboxes];$i++){
$txtboxname = $txt.$i;
echo $txtboxname;
$textbox_value .= $_REQUEST[$txtboxname] ;
$textbox_value .= "
"; //one value per line
echo $textbox_value;
}

}

[rudevils]

hi i tried both the below codes. it is displaying the text box id,but not the user input

if (isset($_REQUEST['Submit'])) { echo $_SESSION[tboxes]; for($i=0;$i < $_SESSION[tboxes];$i++) { $txtboxname=$txt.$i; echo $txtboxname; $textbox_value=$_REQUEST[$txtboxname]; echo $textbox_value; } }

for($i=0;$i < $_SESSION[tboxes];$i++){ $txtboxname = $txt.$i; echo $txtboxname; $textbox_value .= $_REQUEST[$txtboxname] ; $textbox_value .= "
"; //one value per line echo $textbox_value; }

}

hi, there's a mistake in my earlier code
here's the right one ( i've tried it)
first u must make a hidden field in your form for number of textbox
example "" (value automatically fill based on user request)

if($_POST[Submit]) { //if user submit your form
$textbox_value = ""; //initiate value for result
for($i=0;$i <$textbox_num ;$i++){
$txtboxname = "txt".$i; //no $ sign in txt
$textbox_value .= $_POST[$txtboxname]."
";
}
echo "value = $textbox_value"; //print result after "for" loop
}

hope u understand it :D

[lydia21]

thanx its working