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PHP Discussion Thread
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Mar 28th, 2008

function in php

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hi,

this is a simple program it is not working...please do tell me whether my code is correct

PHP Syntax (Toggle Plain Text)
<form>
<?php
function login()
{
 print "<script>";
print " window.location='http://www.webs.com/hi.html'";
 print "</script>";  
}
print "<input type='button' name='butt' value='Apply Online' onClick=login() style='height :2em; width :7em; font-weight:bold; font-size:0.7em' >";
?>
</form>
<form>
<?php
function login()
{
 print "<script>";
print " window.location='http://www.webs.com/hi.html'";
 print "</script>";  
}
print "<input type='button' name='butt' value='Apply Online' onClick=login() style='height :2em; width :7em; font-weight:bold; font-size:0.7em' >";
?>
</form>

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queenc

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Junior Poster

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145 posts
since Mar 2008

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Mar 28th, 2008

Re: function in php

you can't call a php function with an onClick event.. onClick is a javascript/DHTML item.

You also don't even need any of the php opening and closing stuff.
Why cause php to print javascript and html items if you already have form tags outside of the scope of the php?

PHP Syntax (Toggle Plain Text)
<script>
function login(){
window.location='http://www.webs.com/hi.html';
}
</script>
<form>
<input type='button' name='butt' value='Apply Online' onClick='login();' style='height :2em; width :7em; font-weight:bold; font-size:0.7em' >
</form>
<script>
function login(){
window.location='http://www.webs.com/hi.html';
}
</script>
<form>
<input type='button' name='butt' value='Apply Online' onClick='login();' style='height :2em; width :7em; font-weight:bold; font-size:0.7em' >
</form>

Should do the trick.
Although, you really don't even need any of that stuff.
You are just wanting people to go to another page to fill out an application.
This is easily done in html

PHP Syntax (Toggle Plain Text)

<a href="http://www.webs.com/hi.html"><img src="button.gif" /></a>

Sage

sagedavis

Reputation Points: 10

Solved Threads: 6

Junior Poster in Training

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86 posts
since Nov 2007

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Mar 28th, 2008

Re: function in php

no if he is a registered user i want to redirect him to page1.php page or else page2.php...so i taught something like this will help me

kings

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Junior Poster

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107 posts
since Nov 2007

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Mar 29th, 2008

Re: function in php

ok, you still can't call a php function on a javascript event, which is what your code is trying to do.

What you need to do is use your php to print out the html code but make the onclick event itself the value.

Something like this.

PHP Syntax (Toggle Plain Text)
<?PHP
if ($user == $registered){
$onclick = "window.location='http://www.webs.com/page1.html'";
}
else {
$onclick = "window.location='http://www.webs.com/page2.html'";
}
?>
</script>
<form>
<input type='button' name='butt' value='Apply Online' onClick='
<?php echo $onclick; ?>
' style='height :2em; width :7em; font-weight:bold; font-size:0.7em' >
</form>
<?PHP
if ($user == $registered){
$onclick = "window.location='http://www.webs.com/page1.html'";
}
else {
$onclick = "window.location='http://www.webs.com/page2.html'";
}
?>
</script>
<form>
<input type='button' name='butt' value='Apply Online' onClick='
<?php echo $onclick; ?>
' style='height :2em; width :7em; font-weight:bold; font-size:0.7em' >
</form>

Obviosly you will replace user and registered with whatever you use to check users registration...

sagedavis

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Solved Threads: 6

Junior Poster in Training

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86 posts
since Nov 2007

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