Change Form action with Submit button?

Hi,

I have a form with 3 submit buttons.
This is what i want;
Click on button1, form action becomes 1.php
Click on button2, form action becomes 2.php
Click on button3, form action becomes 3.php

I dont want to enter action manual. How can we do this?

Thanks

veledrom

Master Poster

758 posts since Apr 2008

Reputation Points: 42

Solved Threads: 0

3 Years Ago

0

You can either use three different forms with a button in each one, use a javascript function when a button is clicked, or use the html dom in conjunction with javascript.

mychalberry

Newbie Poster

3 posts since Jul 2008

Reputation Points: 10

Solved Threads: 2

3 Years Ago

0

why not try using hidden field where you will set which button you clicked and then call whichever form action you need by testing the hidden field value.

maluisalea

Newbie Poster

2 posts since Feb 2008

Reputation Points: 10

Solved Threads: 1

3 Years Ago

0

you just give different names to your buttons like:

<input type="submit" name="b1">
<input type="submit" name="b2">
<input type="submit" name="b3">

then at the top of your page:
do like this:

<?
ob_start();
if($_POST['b1'])
{
header("location:one.php");
}
if($_POST['b2'])
{
header("location:two.php");
}
if($_POST['b3'])
{
header("location:three.php");
}

Shanti C

Posting Virtuoso

1,642 posts since Jul 2008

Reputation Points: 137

Solved Threads: 162

3 Years Ago

0

you just give different names to your buttons like:

<input type="submit" name="b1">
<input type="submit" name="b2">
<input type="submit" name="b3">

then at the top of your page: do like this:

<?
ob_start();
if($_POST['b1'])
{
header("location:one.php");
}
if($_POST['b2'])
{
header("location:two.php");
}
if($_POST['b3'])
{
header("location:three.php");
}

That will just redirect the page once the button is clicked. To post the form data to different scripts depending upon the button clicked, you need to make use of javascript.

<html>
<head>
</head>
<body>
<form method="post" name="form">
<input type="text" name="name" />
<input type="submit" name="submit1" value="submit1" onclick="javascript: form.action='test1.php';" />
<input type="submit" name="submit2" value="submit2" onclick="javascript: form.action='test2.php';"/>
<input type="submit" name="submit3" value="submit3" onclick="javascript: form.action='test3.php';" />
</form>
</body>
</html>

nav33n

Purple hazed!

Moderator

4,465 posts since Nov 2007

Reputation Points: 524

Solved Threads: 356

3 Years Ago

0

That will just redirect the page once the button is clicked. To post the form data to different scripts depending upon the button clicked, you need to make use of javascript.

ok naveen...
i have understand the thread in that way..

Shanti C

Posting Virtuoso

1,642 posts since Jul 2008

Reputation Points: 137

Solved Threads: 162

3 Years Ago

0

naveen, please tel me the difference between your post and my post....

Shanti C

Posting Virtuoso

1,642 posts since Jul 2008

Reputation Points: 137

Solved Threads: 162

3 Years Ago

0

In your post, it just redirects the user to respective page on button click. It doesn't post the form. In my post, I have specified the action for the form, so it posts the form data to respective script. That is, $_POST['name'] will be available in test1.php, test2.php and test3.php on respective button clicks.

nav33n

Purple hazed!

Moderator

4,465 posts since Nov 2007

Reputation Points: 524

Solved Threads: 356

3 Years Ago

0

k..

Shanti C

Posting Virtuoso

1,642 posts since Jul 2008