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Sep 24th, 2008

PHP Parse error: syntax error, unexpected T_VARIABLE

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Hello

PHP Parse error: syntax error, unexpected T_VARIABLE in /home/mysite/public_html/guestbook/getdrawings.php on line 1

PHP Syntax (Toggle Plain Text)
<?php
 
$dir=opendir("data");
	while ($file=readdir($dir)){
		if(substr($file, -3) == "xml"){
						print 'data/'.$file.'|';
		}
	}
	closedir($dir);
?>
<?php

$dir=opendir("data");
	while ($file=readdir($dir)){
		if(substr($file, -3) == "xml"){
						print 'data/'.$file.'|';
		}
	}
	closedir($dir);
?>

Need your suggestions to solve this problom

regards

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srisree

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Sep 24th, 2008

Re: PHP Parse error: syntax error, unexpected T_VARIABLE

Quote ...

PHP Parse error: syntax error, unexpected T_VARIABLE in /home/mysite/public_html/guestbook/getdrawings.php on line 1

I have tested the provided code both as it currently is and with many different modifications and from what I have found, although with single character changes errors can be made, I don't think that with this code alone that a T_variable error could occure. Especially with line 1 being

PHP Syntax (Toggle Plain Text)

<?php

The only possible error I could see on line one (if you have an odd server) is removing the letters

PHP Syntax (Toggle Plain Text)

php

from line 1. Other than that I would say that a global variable such as ini settings may be interfering with the script.
So basically I just couldn't reproduce the error and was working for me fine.

cwarn23

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Sep 24th, 2008

Re: PHP Parse error: syntax error, unexpected T_VARIABLE

Quote ...

Hello

PHP Parse error: syntax error, unexpected T_VARIABLE in /home/mysite/public_html/guestbook/getdrawings.php on line 1

Dear sisree,

I try this script but show no error.
can u give me php.ini and server details

nikesh.yadav

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Sep 24th, 2008

Re: PHP Parse error: syntax error, unexpected T_VARIABLE

I think there is problem in the directory path once check that if its ok ignore this

srilakshmitr7

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Sep 24th, 2008

Re: PHP Parse error: syntax error, unexpected T_VARIABLE

Hello ! I try this script too, and it works very well ! I think the probleme is out there !

Franky_Fr

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Aug 21st, 2009

Re: PHP Parse error: syntax error, unexpected T_VARIABLE

$connection = mysql_connect($host,$usernamee,$passwordd) or die ('Could not connect to server.');
$db = mysql_select_db($database,$connection) or die ('Could not select database.');
$sqlerror = mysql_error();

//The next line is where the error is, please help me out....
$sqlinsert = "INSERT INTO usercomments(namee, emailaddress, comments, datesent) VALUES ('".$fName."', '".$emaill."', '".$commentt."', '"$datee."')";

$sqlinsertt = mysql_query($sqlinsert) or die ('Could not insert record');

if($sqlinsertt)
{
echo ' RECORD INSERTED SUCCESSFULLY ';
}

else
{
echo ' Record cannot be inserted with Shipper Login: ';
//echo 'error$sqlerror';
}

?>

olammieConcept

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Aug 21st, 2009

Re: PHP Parse error: syntax error, unexpected T_VARIABLE

Click to Expand / Collapse Quote originally posted by olammieConcept ...

$connection = mysql_connect($host,$usernamee,$passwordd) or die ('Could not connect to server.');
$db = mysql_select_db($database,$connection) or die ('Could not select database.');
$sqlerror = mysql_error();

//The next line is where the error is, please help me out....
$sqlinsert = "INSERT INTO usercomments(namee, emailaddress, comments, datesent) VALUES ('".$fName."', '".$emaill."', '".$commentt."', '"$datee."')";

$sqlinsertt = mysql_query($sqlinsert) or die ('Could not insert record');

if($sqlinsertt)
{
echo ' RECORD INSERTED SUCCESSFULLY ';
}

else
{
echo ' Record cannot be inserted with Shipper Login: ';
//echo 'error$sqlerror';
}

?>

First of all welcome to daniweb.
And did you not read my signature saying not to bump old topics. Also please use code tags as they can make it easier to read your post. As for your question, the following code should do the trick:

php Syntax (Toggle Plain Text)
$connection = mysql_connect($host,$usernamee,$passwordd) or die ('Could not connect to server.'); 
$db = mysql_select_db($database,$connection) or die ('Could not select database.');
$sqlerror = mysql_error();
 
$fName=mysql_real_escape_string($fName);
$emaill=mysql_real_escape_string($emaill);
$commentt=mysql_real_escape_string($commentt);
$datee=mysql_real_escape_string($datee);
$sqlinsert = "INSERT INTO usercomments(namee, emailaddress, comments, datesent) VALUES ('$fName', '$emaill', '$commentt', '$datee')";
 
$sqlinsertt = mysql_query($sqlinsert) or die ('Could not insert record'); 
 
if($sqlinsertt)
{
echo '<br><br>RECORD INSERTED SUCCESSFULLY <br>';
}
 
else
{
echo '<br>Record cannot be inserted with Shipper Login:<br> ';
//echo 'error$sqlerror';
}
 
?>
$connection = mysql_connect($host,$usernamee,$passwordd) or die ('Could not connect to server.'); 
$db = mysql_select_db($database,$connection) or die ('Could not select database.');
$sqlerror = mysql_error();

$fName=mysql_real_escape_string($fName);
$emaill=mysql_real_escape_string($emaill);
$commentt=mysql_real_escape_string($commentt);
$datee=mysql_real_escape_string($datee);
$sqlinsert = "INSERT INTO usercomments(namee, emailaddress, comments, datesent) VALUES ('$fName', '$emaill', '$commentt', '$datee')";

$sqlinsertt = mysql_query($sqlinsert) or die ('Could not insert record'); 

if($sqlinsertt)
{
echo '<br><br>RECORD INSERTED SUCCESSFULLY <br>';
}

else
{
echo '<br>Record cannot be inserted with Shipper Login:<br> ';
//echo 'error$sqlerror';
}

?>

cwarn23

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Aug 22nd, 2009

Re: PHP Parse error: syntax error, unexpected T_VARIABLE

Click to Expand / Collapse Quote originally posted by srisree ...

Hello

PHP Parse error: syntax error, unexpected T_VARIABLE in /home/mysite/public_html/guestbook/getdrawings.php on line 1
PHP Syntax (Toggle Plain Text)
<?php
 
$dir=opendir("data");
	while ($file=readdir($dir)){
		if(substr($file, -3) == "xml"){
						print 'data/'.$file.'|';
		}
	}
	closedir($dir);
?>
<?php $dir=opendir("data"); while ($file=readdir($dir)){ if(substr($file, -3) == "xml"){ print 'data/'.$file.'|'; } } closedir($dir); ?>
Need your suggestions to solve this problom

regards

try to use getcwd.

PHP Syntax (Toggle Plain Text)
 
$dirPath = getcwd();  Gets the current working directory
$thePath = $dirPath.'/data/';
$dir=opendir($thePath);
$dirPath = getcwd();  Gets the current working directory
$thePath = $dirPath.'/data/';
$dir=opendir($thePath);

Last edited by phpbeginners; Aug 22nd, 2009 at 12:12 am.

phpbeginners

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