please help

I keep getting this message what is wrong with my sacript???

Parse error: syntax error, unexpected $end in /home/sites/thefieldinggallery.co.uk/web/contact_form.php on line 65

here is the php script:

<?php
/* subject and email Variables */
 $emailSubject = 'Crazy PHP Scripting';
 $webMaster = 'info@thefieldinggallery.co.uk';
 
/* Gathering Data Variables */
 $nameField = $_POST['name'];
 $surnameField = $_POST['surname'];
 $emailField = $_POST['email'];
 $telephoneField = $_POST['telephone'];
 $commentsField = $_POST['comments'];
 
  $body = <<<em
<hr>
name: $name 
surname: $surname 
email: $email 
telephone: $telephone 
comments: $comments 
EOD;
 $headers = "From: $email\r\n";
 $headers ,= "Content-type: text/html\r\n";
 $success = mail($webMaster, $emailSubject, $body, $headers);
 
/*Results rendered as HTML */
 $theResults = <<<EOD
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<table width="50%" border="0" cellspacing="0" cellpadding="0">
  <tr>
    <td colspan="2"><img src="images/strap.jpg" alt="header" width="769" height="216" /></td>
  </tr>
  <tr>
    <td width="11%"><div align="center"><a href="index.html">Back to Home</a></div></td>
    <td width="89%"><div align="center">
      <p>&nbsp;</p>
      <p><font color="#FF0000" size="+7"><u>Thank you</u> <font color="#000000">for your  we have recived you Questions / Comments and we will reply to you</font> <u>as soon as possible</u></font></p>
    </div></td>
  </tr>
  <tr>
    <td>&nbsp;</td>
    <td>&nbsp;</td>
  </tr>
  <tr>
    <td>&nbsp;</td>
    <td><div align="right">Copyright &copy; <a href="http://www.thefieldinggallery.co.uk">www.thefieldinggallery.co.uk</a></div></td>
  </tr>
</table>
</body>
</html>
EOD;
echo "$theresults";
?>

addsf1

Newbie Poster

5 posts since Dec 2008

Reputation Points: 10

Solved Threads: 0

3 Years Ago

0

When using heredoc, you must open and close the variable with the same identifier.

$body = <<<em
<hr>
name: $name 
surname: $surname 
email: $email 
telephone: $telephone 
comments: $comments 
EOD;

should be:

$body = <<<EOD
<hr>
name: $name 
surname: $surname 
email: $email 
telephone: $telephone 
comments: $comments 
EOD;

Also, variables in php are case sensitive, so you'll have a blank page unless you change echo "$theresults"; to echo "$theResults";

buddylee17

Practically a Master Poster

697 posts since Nov 2007

Reputation Points: 232

Solved Threads: 137

3 Years Ago

0

Thank you you are a life saver Cheers bro

addsf1

Newbie Poster

5 posts since Dec 2008

Reputation Points: 10

Solved Threads: 0

3 Years Ago

0

Glad to help.

buddylee17

Practically a Master Poster

697 posts since Nov 2007

Reputation Points: 232

Solved Threads: 137

3 Years Ago

0

Next time, wrap your code in code tags when posting to keep things neat. There are plenty of people here to help out. Keeping things neat will improve your chances of getting help.

buddylee17

Practically a Master Poster

697 posts since Nov 2007

Reputation Points: 232

Solved Threads: 137

3 Years Ago

0

Im new at this and got it from a tutorial. i don't know how to wrap in a tag sorry its messy!
I do have another question though as it has worked and the mail is coming through but the content of the form isn't attached just the headers. can you see what is wrong there???? i would be most grateful

addsf1

Newbie Poster

5 posts since Dec 2008

Reputation Points: 10

Solved Threads: 0

3 Years Ago

0

Wrap the code like so:
[code=php]Code goes here[/code]

As to your problem, your email contains undefined variables. For instance you define namefield as $nameField = $_POST['name']; but in the email you send, you have the undefined variable $name instead of the defined $nameField.

buddylee17

Practically a Master Poster

697 posts since Nov 2007

Reputation Points: 232

Solved Threads: 137

3 Years Ago

0

OK so do i take that as it should look like this?

$nameField = $_POST['nameField'];

I hope im not doing your head in with the questions but as i said i am a total newby at this

addsf1

Newbie Poster

5 posts since Dec 2008

Reputation Points: 10

Solved Threads: 0

3 Years Ago

Show Comments

1

The name the element has in the form goes inside the brackets.
So if your form has

<input name="name" type="text" id="name" tabindex="16" />

After the form is submitted, PHP can assign the value posted to the variable. Here we assign the value of the textbox above to the variable $nameField:

$nameField=$_POST['name'];

Now if you want to use that variable in your email, you'll need to use the variable just defined.

$body = <<<EOD
<hr>
name: $nameField

Get it??

buddylee17

Practically a Master Poster

697 posts since Nov 2007

Reputation Points: 232

Solved Threads: 137

3 Years Ago

0

My Friend as far as i am concerned you are a god in the PHP world
i can not say thank you enough

Cheers

Adam

addsf1

Newbie Poster

5 posts since Dec 2008

Reputation Points: 10

Solved Threads: 0

3 Years Ago

0

My Friend as far as i am concerned you are a god in the PHP world i can not say thank you enough

Cheers

Adam

You can thank to buddylee17, just click on "Add to buddylee17 reputation" in the post that deserves it. There you can also leave short message with your thanks which other member can see and of course mark thread as solved (which you already did)

peter_budo

Code tags enforcer

Moderator

15,436 posts since Dec 2004

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Solved Threads: 902

please help

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