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Apr 26th, 2009

Date Conversion

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In a code routine I receive strings like “04242009” and I need to convert it to April 24, 2009. I have played with several of the date conversion routines but I am getting no where. Help would be appreciated.

Thanks!
WBR

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rouse

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Junior Poster

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Apr 27th, 2009

Re: Date Conversion

apply substring function

PHP Syntax (Toggle Plain Text)
$day=substr("04242009", 0, 1);
$month=substr("04242009", 2, 3);
$year=substr("04242009", 4, 7);
$mydate=$year."-".$month."-".$day;
 
$converted_date=date($mydate,'F d, Y');
$day=substr("04242009", 0, 1);
$month=substr("04242009", 2, 3);
$year=substr("04242009", 4, 7);
$mydate=$year."-".$month."-".$day;

$converted_date=date($mydate,'F d, Y');

Last edited by BzzBee; Apr 27th, 2009 at 2:14 am.

BzzBee

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Posting Whiz

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Apr 27th, 2009

Re: Date Conversion

Thanks for pointing me in the right directions. I had to make some changes to your code and this is what I finally ended up with.
WBR

PHP Syntax (Toggle Plain Text)
        $chopDate =” 04242009";
        $month=substr($chopDate, 0, 2);
        $day=substr($chopDate, 2, 2);
        $year=substr($chopDate, 4, 7);
        $myDate=$month . "/" . $day . "/" . $year;
        $printDate = date("jS F, Y", strtotime ($myDate));
        print ("<h3> <center>$printDate </center></h3>");
 
        $chopDate =” 04242009";
        $month=substr($chopDate, 0, 2);
        $day=substr($chopDate, 2, 2);
        $year=substr($chopDate, 4, 7);
        $myDate=$month . "/" . $day . "/" . $year;
        $printDate = date("jS F, Y", strtotime ($myDate));
        print ("<h3> <center>$printDate </center></h3>");

rouse

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Junior Poster

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Apr 27th, 2009

Re: Date Conversion

it depends on your requirement. i didn't knew your requirement so i just gave an idea with dummy example.

BzzBee

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Posting Whiz

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