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Jul 1st, 2009

Calculate AGE using PHP

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Hi, I want to calculate age of the person using this code

php Syntax (Toggle Plain Text)
<?php
 
/*** a date before 1970 ***/
$dob = strtotime("april 20 1961");
 
/*** another date ***/
$tdate = strtotime("june 2 2009");
 
/*** show the date ***/
echo getAge( $dob, $tdate );
 
?>
<?php

/*** a date before 1970 ***/
$dob = strtotime("april 20 1961");

/*** another date ***/
$tdate = strtotime("june 2 2009");

/*** show the date ***/
echo getAge( $dob, $tdate );

?>

but it gives error
Fatal error: Call to undefined function getage()

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ayesha789

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Jul 1st, 2009

Re: Calculate AGE using PHP

this code working perfectly.

php Syntax (Toggle Plain Text)
<?php
 
 
function yearsOld($birthday)
{
    if (($birthday = strtotime($birthday)) === false)
    {
        return false;
    }
    for ($i = 0; strtotime("-$i year") > $birthday; ++$i);
    return $i - 1;
}  
 
 
 
 /*** example usage ***/
 $birthday = 'april 20 1961';
 
 echo yearsOld($birthday).' years old';
 
?>
<?php


function yearsOld($birthday)
{
    if (($birthday = strtotime($birthday)) === false)
    {
        return false;
    }
    for ($i = 0; strtotime("-$i year") > $birthday; ++$i);
    return $i - 1;
}  



 /*** example usage ***/
 $birthday = 'april 20 1961';
 
 echo yearsOld($birthday).' years old';
 
?>

ayesha789

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Jul 1st, 2009

Re: Calculate AGE using PHP

It is probably faster to do something like:

php Syntax (Toggle Plain Text)
function age($birthday) {
  return date("Y", time() - strtotime($birthday)) - 1970;
}
function age($birthday) {
  return date("Y", time() - strtotime($birthday)) - 1970;
}

It first converts the $birthday string to Unix Time. Which is the number of seconds since the epoch (midnight Jan 1 1970 UTC). http://en.wikipedia.org/wiki/Unix_time

PHP Syntax (Toggle Plain Text)
strtotime($birthday)
strtotime($birthday)

Then subtracts the birthday from the current unix time. This gives you the seconds elapsed between their birthday and today.

PHP Syntax (Toggle Plain Text)
time() - strtotime($birthday)
time() - strtotime($birthday)

Then retrieves the number years that would have elapsed in those seconds, since year 1970.

PHP Syntax (Toggle Plain Text)
date("Y", time() - strtotime($birthday))
date("Y", time() - strtotime($birthday))

Then subtracts 1970 from that, to get the number years since birth (year 0).

Edit: limited to dates php can calculate with unix time.

Last edited by digital-ether; Jul 1st, 2009 at 7:50 am.

digital-ether

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