DELETE FROM table_name WHERE checkbox = checked?

1. pass all record ids in the check box

2. use java script

var recordID= function(){
var a = "";
for(var i=0; i < document.formname.checkboxID.length; i++){
if(document.ks.checkboxID[i].checked == true){
a = a+documentformname.checkboxID[i].value+",";
}
document.formname.action = "filename.php?a=" + a;
}
call this function in submit button
3. PHP code

if(isset($_REQUEST['a']) != '') {
$a = $_REQUEST['a'];
$d=split(",",$a);
$did=array_filter($d);
foreach($did as $i => $value) {
$D = $value;
mysql_query("DELETE FROM table.name where recordid='".$D."' ")or die(mysql_error());
}
unset($did);unset($a);
}
ok thats all...........

Thanks! I know nothing about java script. Do I just copy and paste that code into my php page?

If you are going to use karuppasamy's example, I would make sure you add some protection, check that the values passed are actually numbers. Otherwise you may find that your database is open to attack.

Also, JavaScript is overkill here, no point using it when the same can be acheived simply using HTML and PHP.
1. Make sure all the checkboxes have the same value for name and add [] to indicate it is an array to PHP and set the value to the id of the database row. e.g.

2. In PHP add something along the line of a foreach to see if the box was checked, something like:
You can then use the returned $deleteRecords in your SQL query to. Although the code above is untested and from memory, so you will need to review before using.

Well, I tried that, still no luck...

Xan's example should work (except for a few syntax errors).

in html
<input type="checkbox" name="id[]" value="1">
<input type="checkbox" name="id[]" value="2">
<input type="checkbox" name="id[]" value="3">
<input type="checkbox" name="id[]" value="4">
<input type="checkbox" name="id[]" value="5">
ih PHP
foreach($_POST['id'] as $id ) {
mysql_query("DELETE FROM `table` WHERE `id` = $id") or die(mysql_error());
}
enjoy.....