Oh, shoot, we're both wrong, heh!
This will most DEFINATELY work.
[php]<?php
if (isset($_POST['add'])) {
include ('config.php');
include ('opendb.php');
mysql_select_db('DB_NAME', $mysql);
// You must tell it what the connection resource is, as well
// as which databse you will be using. Make sure that in opendb.php,
// the function mysql_connect(); is being set to $mysql.
$username = $_POST['username'];
$password = $_POST['password'];
$query = "INSERT INTO user (host, user, password, select_priv, insert_priv, update_ priv) VALUES ('localhost', '" . $username . "', 'PASSWORD(" . $password . "'), 'Y', 'Y', 'Y')";
// You need to concatenate with the '.' command.
// I know this will work, I've used it hunderds of times.
mysql_query($query) or die('Error, insert query failed ');
$query2 = "FLUSH PRIVILEGES";
mysql_query($query2) or die('Error, insert query failed');
include ('closedb.php');
echo "New MySQL user added";
} else {
?>
<html><body>
<form method="post">
<table width="400" border="0" cellspacing="1" cellpadding="2">
<tr>
<td width="100">Username</td>
<td><input name="username" type="text" id="username"></td>
</tr>
<tr>
<td width="100">Password</td>
<td><input name="password" type="text" id="password"></td>
</tr>
<tr>
<td width="100"> </td>
<td> </td>
</tr>
<tr>
<td width="100"> </td>
<td><input name="add" type="submit" id="add" value="Add New User"></td>
</tr>
</table>
</form></body></html>[/php]