I don't think so. Just from using it enough, I believe it takes the format from the date(), so a variable would do nothing. If you want to print a date with your variables, I would suggest doing something such as this:

If the value of $day-$month-$year evaluates to a string like 'd-m-Y' or any other combination of php date formats then yes you could.


If the value of $day-$month-$year evaluates to an actual date string like '31-8-2010' then no you can not feed that to the date function.

You would need to use strtotime or the DateTime object. I would suggest the later as it is compatible with dates after 2038, among countless other benefits.



Hopefully this helps.

thanks hey

$format = "$day-$month-$year"; // 31-8-2010
echo date('d-m-Y', strtotime($format)); // 31-08-2010
echo strtotime($format); // 1283308069 or something

------> 04-09-20101283558400

$format = "$day-$month-$year"; // 31-8-2010
$date = new DateTime($format);
echo $date->format('d-m-Y'); // 31-8-2010
echo $date->getTimestamp(); //1283308069 or something

------> 04-09-20101283558400

thanks for the two above they both return the same date value's for the data that was entered. however is it possible to have all the numbers after 2010 to disapear?
and maybe have it in 04 Sept 2010 format???

been tryin but getting nowhere. if you can help i would greatly appriciate it.

well got the date to look like 04 Sept 2010 however still have the time stamp after.

is there anyway of me getting rid of it???

gary

got it!!!!!!!

just needed to take out the one 'echo'. hahaha

thanks