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How to Exclude Some Result From a Particular Row of Table from Showing

I am using mysql_fetch_array to fetch result from a table of my database and I want to exclude results from particular users from being fetch together with others.
Example:

$result = mysql_query("SELECT * FROM users") 
                or die(mysql_error());  
                
        
        
        echo "<table border='1' cellpadding='10'>";
        echo "<tr> <th>ID</th> <th>First Name</th> <th>Last Name</th> <th>Sex</th> <th>Username</th></tr>";

        while($row = mysql_fetch_array( $result )) {
                
                // echo out the contents of each row into a table
                echo "<tr>";
                echo '<td>' . $row['id'] . '</td>';
                echo '<td>' . $row['firstname'] . '</td>';
                echo '<td>' . $row['lastname'] . '</td>';
                echo '<td>' . $row['sex'] . '</td>';
                echo '<td>' . $row['username'] . '</td>';
                echo "</tr>"; 
        } 

        echo "</table>";

Example Results
ID First Name Last Name Sex Username
1 Adams John Male adamsjo
2 Jen Jensen Female jensenjen
3 Mark Mike Male miker
4 Mathew Denson Male denis
etc

How can i exclude results from the first two rows of ID 1 and 2 from showing together with the rest of the result?

deyesborn
Newbie Poster
7 posts since Aug 2010
Reputation Points: 10
Solved Threads: 0
 
'SELECT * FROM users where id > 2'
diafol
Rhod Gilbert Fan (ardav)
Moderator
7,792 posts since Oct 2006
Reputation Points: 1,170
Solved Threads: 1,080
 

Wow! I just used this query and it works:

$result = mysql_query("SELECT * FROM users WHERE id NOT IN ('1', '2')") 
                or die(mysql_error());
deyesborn
Newbie Poster
7 posts since Aug 2010
Reputation Points: 10
Solved Threads: 0
 

@Ardav, thanks so much, that also work well

deyesborn
Newbie Poster
7 posts since Aug 2010
Reputation Points: 10
Solved Threads: 0
 

This question has already been solved

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