Autocomplete jquery PHP Access Database
Hi All,
I've hit a brick wall trying to get the jquery autocomplete to work correctly. The problem is with the .php file and the way the While loop works, as what it does is create a array for every name rather than one single array. I've tried to move the 'echo json_encode' outside of the loop but then it only returns the very last value.
So question is how do I make the While function build an array of every distinct name in the database then echo as json_encode.
Thanks
CODE:
<?php
$conn = new COM("ADODB.Connection") or die("Cannot start ADO");
$conn->Open("DRIVER={Microsoft Access Driver (*.mdb)}; DBQ=C:\\Admin.mdb");
$queryString = $_GET['term'];
$query = "SELECT DISTINCT [PersonNameFirst] FROM Person WHERE PersonNameFirst like '$queryString%'";
$result = $conn->Execute($query);
while (!$result->EOF)
{
$fz = $result->Fields("PersonNameFirst");
$array = array($fz->value);
$result->MoveNext();
$output = $array;
echo json_encode($output);
}
?>
brenton_77
Newbie Poster
18 posts since Jun 2010
Reputation Points: 10
Solved Threads: 0
Skill Endorsements: 0
at line 15 you are creating a new array for each and every record thats giving the invalid output to you
move that declarion out side of the while loop and make changes as follows
$my_array = array();
$rec_count =0;
while (!$result->EOF)
{
$fz = $result->Fields("PersonNameFirst");
$my_array[$rec_count] = $fz->value ;
$result->MoveNext();
$rec_count++;
}
echo json_encode($my_array);
please check it once
let me know the status
radhakrishna.p
Posting Whiz in Training
263 posts since Nov 2012
Reputation Points: 29
Solved Threads: 59
Skill Endorsements: 10
Hi radhakrishna,
That worked perfectly I am now seeing a single array of results. Just one more question
On the line "$my_array[$rec_count] = $fv->value ' ' $fz->value" how do I get it join first name and lastname together with a space in between e.g. "John Smith"? json complain about my formatting.
Thanks again.
$query = "SELECT DISTINCT [PersonNameLast], [PersonNameFirst] FROM Person WHERE PersonNameFirst like '$queryString%'";
$result = $conn->Execute($query);
$my_array = array();
$rec_count = 0;
while (!$result->EOF)
{
$fv = $result->Fields("PersonNameFirst");
$fz = $result->Fields("PersonNameLast");
$my_array[$rec_count] = $fv->value ' ' $fz->value;
$result->MoveNext();
$rec_count++;
}
echo json_encode($my_array);
brenton_77
Newbie Poster
18 posts since Jun 2010
Reputation Points: 10
Solved Threads: 0
Skill Endorsements: 0
replace this $my_array[$rec_count] = $fv->value ' ' $fz->value;
with the following
$my_array[$rec_count] = $fv->value.' '.$fz->value;
in php '.' is used for concatenating operations
please check it
and let me know the status
happy coding
radhakrishna.p
Posting Whiz in Training
263 posts since Nov 2012
Reputation Points: 29
Solved Threads: 59
Skill Endorsements: 10
It worked. Thanks again for your help
brenton_77
Newbie Poster
18 posts since Jun 2010
Reputation Points: 10
Solved Threads: 0
Skill Endorsements: 0
Question Answered as of 3 Months Ago by
radhakrishna.p