this regular expression

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Why is this regular expression (pat) not working? According to documentation, scan takes both string and regexp.

Ruby Syntax (Toggle Plain Text)
irb(main):001:0> pat = '\d+ (\w+) \(\d+\)'
=> "\\d+ (\\w+) \\(\\d+\\)"
irb(main):002:0> string = 'dfasdf 1 up (2009) sdfasdf 2 walle (2008) adfasdf'
=> "dfasdf 1 up (2009) sdfasdf 2 walle (2008) adfasdf"
irb(main):003:0> string.scan(pat)
=> []
irb(main):001:0> pat = '\d+ (\w+) \(\d+\)'
=> "\\d+ (\\w+) \\(\\d+\\)"
irb(main):002:0> string = 'dfasdf 1 up (2009) sdfasdf 2 walle (2008) adfasdf'
=> "dfasdf 1 up (2009) sdfasdf 2 walle (2008) adfasdf"
irb(main):003:0> string.scan(pat)
=> []

Thanks.

johndoe444

Reputation Points: 11

Solved Threads: 0

Posting Whiz in Training

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since Feb 2008

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Oct 29th, 2009

Re: this regular expression

Ruby Syntax (Toggle Plain Text)
 
pat = '(\d+)'
string = 'dfasdf 1 up (2009) sdfasdf 2 walle (2008) adfasdf'
p string.scan(/#{pat}/)
=>[["1"], ["2009"], ["2"], ["2008"]]
pat = '(\d+)'
string = 'dfasdf 1 up (2009) sdfasdf 2 walle (2008) adfasdf'
p string.scan(/#{pat}/)
=>[["1"], ["2009"], ["2"], ["2008"]]

xml_looser

Reputation Points: 16

Solved Threads: 21

Junior Poster

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since Apr 2009

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Oct 29th, 2009

Re: this regular expression

nice work.

Click to Expand / Collapse Quote originally posted by xml_looser ...

Ruby Syntax (Toggle Plain Text)
 
pat = '(\d+)'
string = 'dfasdf 1 up (2009) sdfasdf 2 walle (2008) adfasdf'
p string.scan(/#{pat}/)
=>[["1"], ["2009"], ["2"], ["2008"]]
pat = '(\d+)' string = 'dfasdf 1 up (2009) sdfasdf 2 walle (2008) adfasdf' p string.scan(/#{pat}/) =>[["1"], ["2009"], ["2"], ["2008"]]

johndoe444

Reputation Points: 11

Solved Threads: 0

Posting Whiz in Training

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since Feb 2008

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