Regular Expression Help!

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I need to check if two parameter names exists in the url. If any of them do i need to replace the value of the parameter.

I can match the parameter name, but i am not sure how to replace the value. The two parameters/values would be at the end of the url.

what i have so far is below.

HTML and CSS Syntax (Toggle Plain Text)
url = “http://www.daniweb.com?parm1=value&parm2=value&parm3=value&parm4=value
 
// can i combine these some how?
var parm3RegExp = /parm3=/;
var parm4RegExp = /parm4=/;
 
// finds parm3. Now how can i replace the value?
url = parm3RegExp.exec(url)
url = “http://www.daniweb.com?parm1=value&parm2=value&parm3=value&parm4=value

// can i combine these some how?
var parm3RegExp = /parm3=/;
var parm4RegExp = /parm4=/;

// finds parm3. Now how can i replace the value?
url = parm3RegExp.exec(url)

I was thinking about something like below. but i want to replace the parameter value and not the name

HTML and CSS Syntax (Toggle Plain Text)

var url = url.replace(/parm3=/, "");

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Sailor_Jerry

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Jun 2nd, 2006

Re: Regular Expression Help!

Got this to work.
I will just remove the parameters and the values if they are present in the url. Then run the logic to create and add the paramters and there values to the url, if they are needed.

HTML and CSS Syntax (Toggle Plain Text)
url = “http://www.daniweb.com?parm1=value&parm2=value&parm3=value&parm4=value
var urlParm3loc = url.search(/&parm3=/);
var urlParm4loc = url.search(/&parm4=/);
 
if(urlParm3loc  > 0 || urlParm4loc > 0)
  {
	var startIndex = urlParm3loc > urlParm4loc  ? urlParm4loc  : urlParm3loc ;
	url = url.replace(url.substring(startIndex,url.length),"");
  }
url = “http://www.daniweb.com?parm1=value&parm2=value&parm3=value&parm4=value
var urlParm3loc = url.search(/&parm3=/);
var urlParm4loc = url.search(/&parm4=/);

if(urlParm3loc  > 0 || urlParm4loc > 0)
  {
	var startIndex = urlParm3loc > urlParm4loc  ? urlParm4loc  : urlParm3loc ;
	url = url.replace(url.substring(startIndex,url.length),"");
  }

Sailor_Jerry

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